在多行文本中捕获多个字符串

Question

Iv'e been at it for some time now, I'm trying to extract a number of values from a string pattern in a multiline text using re.findall with no luck.

text:

RX[0]
qpn : 0x48
cqn : 0x80
rxBytes : 179531811
rxPackets : 296242
rxPacketsDropped : 0
rxCheckSumOk : 225257
rxCheckSumNone : 200
RX[1]
qpn : 0x49
cqn : 0x81
rxBytes : 0
rxPackets : 0
rxPacketsDropped : 0
rxCheckSumOk : 0
rxCheckSumNone : 0**

i need to extract the index -> RX[index] and the rxPackets : value

if i split to sections than i can use -

re.findall('RX\[(\d+)\].*rxPackets\s*:\s*(\d+)', section, re.DOTALL)

but i'm looking to do this with a single regex pattern. can any one help me shed some light on how to do this?

Answer 1

This works:

>>> txt='''\
... RX[0]
... qpn : 0x48
... cqn : 0x80
... rxBytes : 179531811
... rxPackets : 296242
... rxPacketsDropped : 0
... rxCheckSumOk : 225257
... rxCheckSumNone : 200
... RX[1]
... qpn : 0x49
... cqn : 0x81
... rxBytes : 0
... rxPackets : 0
... rxPacketsDropped : 0
... rxCheckSumOk : 0
... rxCheckSumNone : 0**
... '''
>>> import re 
>>> re.search(r'RX\[(\d+)\].*?rxPackets\s+:\s+(\d+)', txt, re.S).groups()
('0', '296242')

Or, with findall:

>>> re.findall(r'RX\[(\d+)\].*?rxPackets\s+:\s+(\d+)', txt, re.S)
[('0', '296242'), ('1', '0')]

Compare with using the greedy form of .* :

>>> re.findall(r'RX\[(\d+)\].*rxPackets\s+:\s+(\d+)', txt, re.S)
[('0', '0')]

Which you can see visually here for greedy and not greedy

Answer 2

I am too stupid to use a regex to solve this.

rxDict = dict()
key = ''
for line in lines:
    if 'RX' in line:
    key = line.split('[')[-1].split(']')[0]
    if key != '':
       if 'rxPackets' in line:
            rxDict[key] = line.split(':').strip()
            key = ''