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Scala-代数运算字符串

[英]Scala - string of algebraic operations

I have a string representing some basic algebraic operations, for example: 我有一个表示一些基本代数运算的字符串,例如:

 "42 * 67 + 4"

I would like a function of type 我想要一个类型的函数

 function (operation: String) : Int = {}

such that it takes a string of algebraic operations and returns the actual final value, in this case: 2818 这样它需要一串代数运算并返回实际的最终值,在这种情况下:2818

I would know how to extract the numbers from such a string but I do not have clear how to extract the mathematical operations such as '+', '-', '*', '/' and actually compute them. 我会知道如何从这样的字符串中提取数字,但是我还不清楚如何提取诸如“ +”,“-”,“ *”,“ /”之类的数学运算并实际进行计算。

It's fairly simple to implement the Shunting-yard algorithm to do this sort of calculations without any external libraries: 在没有任何外部库的情况下,实现Shunting-yard算法来进行这种计算非常简单:

def calculate(operation: String): Int = {
  var results: List[Int] = Nil
  var operators: List[String] = Nil

  def precedence(operator: String) = operator match {
    case "+" | "-" => 0
    case "*" | "/" => 1
  }

  def execute(operator: String): Unit = {
    (results, operator) match {
      case (x :: y :: rest, "+") => results = (y + x) :: rest
      case (x :: y :: rest, "-") => results = (y - x) :: rest
      case (x :: y :: rest, "*") => results = (y * x) :: rest
      case (x :: y :: rest, "/") => results = (y / x) :: rest
      case (_, _) => throw new RuntimeException("Not enough arguments")
    }
  }

  for (term <- "[1-9][0-9]*|[-+/*]".r.findAllIn(operation)) {
    util.Try(term.toInt) match {
      case util.Success(number) => results ::= number
      case _ =>
        val (operatorsToExecute, rest) = 
          operators.span(op => precedence(op) >= precedence(term))
        operatorsToExecute foreach execute
        operators = term :: rest
    }
  }
  operators foreach execute

  results match {
    case res :: Nil => res
    case _ => throw new RuntimeException("Too many arguments")
  }
}

This uses integer division: 这使用整数除法:

scala> calculate("3 / 2")
res0: Int = 1

And has correct precedence of addition and multiplication: 并具有正确的加法和乘法优先级:

scala> calculate("2 + 2 * 2")
res1: Int = 6

Support of: 支持:

  • more kinds of operations, 更多的操作,
  • parentheses, eg 2 * (2 + 2) , 括号,例如2 * (2 + 2)
  • floating-point calculations, 浮点计算
  • better testing of the formula content (currently it simply ignores all characters except numbers and operators) 更好地测试公式的内容(目前,它只忽略数字和运算符以外的所有字符)
  • not throwing errors (for example, returning Try[Int] , Option[Int] , etc. instead of the current behaviour of returning a bare Int or throwing an error) 不抛出错误(例如,返回Try[Int]Option[Int]等,而不是返回裸Int或抛出错误的当前行为)

is left as an exercise to the reader. 留给读者练习。

For more complex things, of course it would be better to use scala-parser-combinators or some third-party parsing library as proposed in other answers. 对于更复杂的事情,当然最好使用scala-parser-combinators或其他答案中建议的某些第三方解析库。

So, @Gábor Bakos posted his joking comment, while I was still composing and testing my joking answer, but I'll post it anyway. 因此,@GáborBakos发布了他的笑话评论,而我仍在撰写和测试我的笑话答案,但无论如何我都会将其发布。

Note: it works. 注意:有效。 Sometimes. 有时。 A bit. 一点点。 Note2: it's a joke! 注意2:这是个玩笑!

def function(operation: String) = {
  val js = new javax.script.ScriptEngineManager().getEngineByName("JavaScript")
  js.eval(operation) match { case i: Integer => i.asInstanceOf[Int] }
}

function("42 * 67 + 4")
// => 2818 : Int

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