变音符号的正则表达式

Question

I'm looking to implement the solution provided in this answer but it's not working. The code in this jsFiddle have looks like this:

function Start() {

    $('#TheBox').keyup(function () {

        var TheInput = $('#TheBox').val();      
        var TheCleanInput = TheInput.replace(/([.\p{L}])/g, '');

        $('#TheBox').val(TheCleanInput);
    });
}

$(Start);

Basically, I'm looking to allow letters such as é è ô as well as numbers. What do I need to change to make the regex filter work?

Answer 1

As Casimir et Hippolyte stated in comments, Javascript does not support \\p{L} unicode character class.

You can create your own character class:

[a-zA-Z0-9À-ž]

Demo

If you want to allow those characters but replace characters outside those ranges, negate the character classes:

[^a-zA-Z0-9À-ž]

Demo

Or as pointed out in comments:

[A-zÀ-ÖØ-öø-įĴ-őŔ-žǍ-ǰǴ-ǵǸ-țȞ-ȟȤ-ȳɃɆ-ɏḀ-ẞƀ-ƓƗ-ƚƝ-ơƤ-ƥƫ-ưƲ-ƶẠ-ỿ]

Answer 2

The [À-ž] character class includes the following characters, highlighted in yellow below.

Answer 3

If someone looking for only polish diacritics: [A-Za-zĄ-ćĘęÓóŁ-ńŚśŹ-ż] .

Answer 4

When using Java you can use a java regex for this:

import java.util.regex.Pattern;

public class WhitelistValidator {

    private static final String ANY_LETTER = "\\p{L}"; // includes diacritics
    private static final String NUMERIC = "0-9";
    public static final Pattern PATTERN = Pattern.compile(String.format("[%s%s]+", ANY_LETTER, NUMERIC));

    public boolean isValid(String valueUnderTest) {
        return PATTERN.matcher(valueUnderTest).matches();
    }
}

See https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html