[英]Scraping the second page of a website in Python does not work
Let's say I want to scrape the data here . 假设我要在这里抓取数据。
I can do it nicely using urlopen
and BeautifulSoup
in Python 2.7. 我可以在python 2.7中使用urlopen
和BeautifulSoup
很好地做到这一点。
Now if I want to scrape data from the second page with this address . 现在,如果我想使用该地址从第二页抓取数据。
What I get is the data from the first page! 我得到的是第一页的数据! I looked at the page source of the second page using "view page source" of Chrome and the content belongs to first page! 用Chrome的“查看页面源”看了第二页的页面源,内容属于第一页!
How can I scrape the data from the second page? 如何从第二页抓取数据?
The page is of a quite asynchronous nature, there are XHR requests forming the search results, simulate them in your code using requests
. 该页面具有非常异步的性质,有XHR请求构成搜索结果,并使用requests
在代码中模拟它们。 Sample code as a starting point for you: 示例代码是您的起点:
from bs4 import BeautifulSoup
import requests
url = 'http://www.amazon.com/Best-Sellers-Books-Architecture/zgbs/books/173508/#2'
ajax_url = "http://www.amazon.com/Best-Sellers-Books-Architecture/zgbs/books/173508/ref=zg_bs_173508_pg_2"
def get_books(data):
soup = BeautifulSoup(data)
for title in soup.select("div.zg_itemImmersion div.zg_title a"):
print title.get_text(strip=True)
with requests.Session() as session:
session.get(url)
session.headers = {
'User-Agent': 'Mozilla/5.0 (Linux; U; Android 4.0.3; ko-kr; LG-L160L Build/IML74K) AppleWebkit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30',
'X-Requested-With': 'XMLHttpRequest'
}
for page in range(1, 10):
print "Page #%d" % page
params = {
"_encoding": "UTF8",
"pg": str(page),
"ajax": "1"
}
response = session.get(ajax_url, params=params)
get_books(response.content)
params["isAboveTheFold"] = "0"
response = session.get(ajax_url, params=params)
get_books(response.content)
And don't forget to be a good web-scraping citizen and follow the Terms of Use. 并且不要忘记成为一名良好的网络爬虫公民并遵守使用条款。
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