使用cmd批处理查找具有相同文件名的所有文件

Question

For example, in a directory, I have N .eps files named name1.eps, name2.eps, ... and also much more pdf files. But within these pdf files, there are exactly N pdf files with the same filename as eps files, that is name1.pdf, name2.pdf,... .

So I want a batch that can scan the current dir, give a list of all eps files and corresponding list of pdf files.

finally I want another batch named convert.bat which takes two parameters to run a series of command as below

convert.bat name1.eps name1.pdf
convert.bat name2.eps name2.pdf
.....
.....

the convert.bat first compares the modified time of name.eps and name.pdf, and if the modified time of name.eps is newer than name.pdf, then it will run epstopdf name.eps , otherwise it will do nothing.

I am really a newbie in using cmd batch. could somebody teach me how to realize the whole process I mentioned above. Thank you so much!

Answer 1

I figure out a way. The following batch file do the whole job.

SETLOCAL ENABLEDELAYEDEXPANSION

for %%G in (*.eps) do @if not exist "%%~nG.pdf" (epstopdf "%%G") else (
(for /f "delims=" %%i in ('dir /B /O:D "%%G" "%%~nG.pdf"') do set newest=%%~xi) & (
if !newest!==.eps epstopdf "%%G"))