[英]SimpleDateFormat.parse() - generates wrong date for different date-formats
Below is my code to parse the date using SimpleDateFormat with pattern: 下面是我使用SimpleDateFormat模式解析日期的代码:
String pattern = "yyyy-MM-dd";
SimpleDateFormat format = new SimpleDateFormat(pattern);
try {
Date date = format.parse("05-21-2030");
System.out.println(date);
} catch (ParseException e) {
e.printStackTrace();
}
You can see the date which I passed to parse is different from date format which is specified in SimpleDateFormat. 您可以看到我传递给解析的日期与SimpleDateFormat中指定的日期格式不同。 In this case I was expecting kind of excpetion as format is different but it parsed successfully with some different date values.
在这种情况下,由于格式不同,我希望有一种解雇,但它使用一些不同的日期值成功解析。 I got the output - Tue Mar 22 00:00:00 IST 12
我得到了输出 - Tue Mar 22 00:00:00 IST 12
When I pass the same format like 2030-05-21 it works fine. 当我传递相同的格式,如2030-05-21,它工作正常。
Can you guys please let me know how can I prevent such things in my code? 你能告诉我如何在我的代码中阻止这些事情吗?
Basically you want SimpleDateFormat
to be strict, so set lenient to false. 基本上你希望
SimpleDateFormat
是严格的,所以将lenient设置为false。
SimpleDateFormat format = new SimpleDateFormat(pattern);
format.setLenient(false);
If you can afford using Java 8 time API, its formatter works as expected: 如果您能负担得起使用Java 8时间API,其格式化程序将按预期工作:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd");
try {
LocalDate date = LocalDate.parse("2030-05-21", formatter);
System.out.println(date);
LocalDate date2 = LocalDate.parse("05-21-2030", formatter);
System.out.println(date2);
} catch (DateTimeParseException e) {
e.printStackTrace();
}
Output: 输出:
2030-05-21
java.time.format.DateTimeParseException: Text '05-21-2030' could not be parsed at index 0
at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1947)
at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1849)
at java.time.LocalDate.parse(LocalDate.java:400)
at java8.Snippet.main(Snippet.java:25)
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