是否可以在同一活动中执行单独的网络线程而无需等待？

Question

I am performing two class which is extending ASyncTask and both have different functions but because of the second class my first class is lagging. So what i want to know is, is there any better solution to code in such a way that both of the operation will perform the task without making other operation to wait?

Updated with code For the first call in the onCreate()

new connection().execute(); //

Some task performed by the same class called

 public class connection extends AsyncTask {
    @Override
    protected Object doInBackground(Object... arg0) {
       //some operation
        return value;
    }

    @Override
    protected void onPostExecute(Object o) {
        super.onPostExecute(o);
        String m = String.valueOf(o);
        if (o != null) {
           someoperation
        } else {
            edittxt.setTextColor(Color.RED);
            edittxt.setText("No Internet Connection");
        }
    }
}

similarly i am performing the other class that i have.

Answer 1

您可以将AsyncTask.executeOnExecutor与THREAD_POOL_EXECUTOR一起THREAD_POOL_EXECUTOR ，默认执行者为SERIAL_EXECUTOR 。

Answer 2

You can create two separate threads and perform your operations. It will quarantine, that all operations will be performed async.

final Handler handler = new Handler();

        Thread operation1 = new Thread(new Runnable() {
            @Override
            public void run() {
                doOperation1();
                handler.run(new Runnable(){
                    @Override
                    public void run() {
                        onPostExecute1();
                    }
                });
            }
        });

        Thread operation2 = new Thread(new Runnable() {
            @Override
            public void run() {
                doOperation2();
                handler.run(new Runnable(){
                    @Override
                    public void run() {
                        onPostExecute2();
                    }
                });
            }
        });

        operation1.start();
        operation2.start();