[英]Iterate over all files in directory from a specified relative path
I want to use this kind of "relative" path, because I want to be able to include all the files in this directory as part of a github project that others can download and just run. 我想使用这种“相对”路径,因为我希望能够将此目录中的所有文件作为github项目的一部分包含在其他人可以下载并运行的项目中。
So I want to just jump up once in the structure ../
and then go down into one of the directories there, word_lists_1
and read out all the files. 所以我想在结构中跳起一次../
然后进入其中一个目录, word_lists_1
并读出所有文件。
6 th 6 日
This code keeps crashing though. 这段代码虽然不断崩溃。 Why is that? 这是为什么?
public static void main(String[] args)
{
ArrayList<File> arrayList = new ArrayList<File>();
final String directoryName = "../word_lists_1";
listf( directoryName, arrayList );
for(File elem : arrayList)
{
System.out.println(elem+" ");
}
}
public static void listf(String directoryName, ArrayList<File> files)
{
File directory = new File(directoryName);
// get all the files from a directory
File[] fList = directory.listFiles();
for (File file : fList)
{
if (file.isFile())
{
files.add(file);
}
else if (file.isDirectory())
{
listf(file.getAbsolutePath(), files);
}
}
}
This is the error message: 这是错误消息:
Exception in thread "main" java.lang.NullPointerException
at Main.listf(Main.java:49)
at Main.main(Main.java:27)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:497)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:140)
so it doesn't like line 49
which is this: 所以它不喜欢第49
行:
for (File file : fList)
You may need the file canonical path to resolve the parent accordingly and avoid any path to be unresolved which may need to a some being null
, hence the NullPointerException
. 您可能需要文件规范路径来相应地解析父级,并避免任何未解析的路径,这可能需要一些为null
,因此NullPointerException
。
One simple implementation to resolve the a directory out of a realtive path to the current directory then display of load its tree hierarchy would be as follows: 一个简单的实现,用于解析当前目录的实际路径中的目录,然后显示其树层次结构的加载如下:
public class Main
{
public static void main( String[] args ) throws URISyntaxException, IOException
{
File currentDir = new File( "." ); // Read current file location
File targetDir = null;
if (currentDir.isDirectory()) {
File parentDir = currentDir.getCanonicalFile().getParentFile(); // Resolve parent location out fo the real path
targetDir = new File( parentDir, "word_lists_1" ); // Construct the target directory file with the right parent directory
}
if ( targetDir != null && targetDir.exists() )
{
listDirectoryAndFiles( targetDir.toPath() );
}
}
private static void listDirectoryAndFiles( Path path ) throws IOException
{
DirectoryStream<Path> dirStream = Files.newDirectoryStream( path );
for ( Path p : dirStream )
{
System.out.println( p.getFileName() );
if ( p.toFile().isDirectory() )
{
listDirectoryAndFiles( p );
}
}
}
}
You may just need to adjust the listDirectoryAndFiles(java.nio.file.Path)
method to meet your needs. 您可能只需要调整listDirectoryAndFiles(java.nio.file.Path)
方法即可满足您的需求。
Note that the aforementioned implementation uses the new I/O capabilities out of Java 7. 请注意,上述实现使用Java 7之外的新I / O功能。
This is what I understand from your requirements 这是我从您的要求中理解的
if I understand your question correctly ,I would have implemented it like 如果我正确理解你的问题,我会像它一样实现它
String str=System.getProperty("user.dir");
String filePath = str+"/../word_lists_1";
if you are in some other directory then you can do 如果您在其他目录中,那么您可以这样做
String str=Paths.get(".").toAbsolutePath().normalize().toString();
String filePath = str+"/../word_lists_1";
hope this helps! 希望这可以帮助!
good luck! 祝好运!
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