SQL 选择列进行比较

Question

I have a SQL table which have a column named keywords .

Table:

| id | keywords |

| 0 | music programming guitar |

Now i have an array like $array = array("boat", "water", "music"); .

My target is to select all columns which have at least one of the things from the array in the keywords .

Sql-Query:

"SELECT * FROM table WHERE keywords IN ('".$array."')";

It returns nothing.

Answer 1

The approach I am going to describe is highly not recommended. The correct approach is to have a separate table with one row per id and keyword . This is a junction table, and it would have rows like:

id       keyword
1        music
1        programming
1        guitar

This is the right way to store lists in a relational database. Databases have this great data structure for lists. It is called a table, not a string.

But, if you are really stuck with this situation, then you can hack your way to a solution. Presumably, performance is not an issue.

The hack is to format your list as a regular expression, and create the where clause as:

where keywords regexp 'boat|water|music'