在矩阵的单元格数组中查找元素的索引

Question

I want to find the index(that's in row and column) of a specific matrix in a cell array of matrices, for example if I have

A = [2 3;4 1]

and

B = {[2 2;1 1] [2 3;4 1] [1 1;1 1]}

then I want to return 2 (because B{2}==A ).

I want to solve this without for , although I don't have to, the cell array is basically small, but I want to do it without for anyway.

I searched for this and found this and this on SO but their solution only work for strings which I don't have here.

So how to solve this without for -loop ?

Note

A is an ordinary matrix not a single element cell array, B is a cell array of matrices.

Answer 1

Some possibilities:

• Use cellfun with isequal to test each element of B for equality:

   find(cellfun(@(x) isequal(x,A), B)) 

• If all matrices have the same size : concatenate into a 3D array (or better yet, use a 3D array from the beginning), and use bsxfun for the comparison:

   find(all(all(bsxfun(@eq, A, cat(3, B{:})),1),2))