符号而不是空格的Javascript正则表达式

Question

I want to test a string for a symbol (eg $%^&* ) so I use the following regex that works well:

/[\W+]/.test(string)

However, a space is also matched with this regex. What I really want is to test for a symbol but not a space. I'm trying the following code, but a space is still matched:

/[\W\S+]/.test(string)

Is there a better way to do this?

Answer 1

Since the whitespaces are included in \\W , you need to use a negated character class:

[^\w\s]

However, you must clearly define what you call a "symbol" since this character class include for example accentued letters and all out of the ascii range.

Answer 2

\\W is the equivalent of [^A-Za-z0-9_] , meaning "any character except these." So you can use [^A-Za-z0-9_ ] (note the space at the end) to exclude spaces.

Answer 3

You may use the inverse shorthand character class for \\W (which is \\w ) and use a negation in the character class:

/[^\w\s]+/.test(string)

Your regex [\\W\\S+] is also matching literal + as it is part of a character class. I think you need to place it outside the class to match 1 or more characters.

Answer 4

This regex may help you: [^\\s\\w]

https://regex101.com/r/jO4uU6/3

Answer 5

You may try this also.

(?!\s)\W

This would match any non-word character but not of a space.

/(?:(?!\s)\W)+/.test(string)

ie, match one or more non-word characters but not of a space.

DEMO