Javascript使用正则表达式替换

Question

I want to replace start from @ to º with 0 below is my string

I try its working only for 2 pair but not working for 3 etc pair

Example 01:

Input Data

@8~Cº + @9~Cº

Output

0 + 0

Example 02:

Input Data

@11~Cº + @12~P1º - @13~Fº

Output

0+0+0

Below is my code

var tempRes = "@11~Cº + @12~P1º - @13~Fº";
tempRes = tempRes.replace(/@[0-9]~[A-Z]º/i,parseFloat(0));

Answer 1

You can do:

var s = '@11~Cº + @12~P1º + @13~Fº'
var r = s.replace(/@[^º]+º/g, 0);
//=> 0 + 0 + 0

---

EDIT: To remove spaces also

var r = s.replace(/\s*@[^º]+º\s*/g, 0);
//=> 0+0+0

Answer 2

you can use this regular expression to catch what you want

@.+?º

try this demo

Demo

to remove spaces use this regex

\s*@.+?º\s*

try this Demo

var input = '@11~Cº + @12~P1º + @13~Fº'
var output = input.replace(/\s*@.+?º\s*/g, 0)

Answer 3

I would use this regex in case you have multiple lines in your input:

[ ]*@[^º\n]*º[ ]*

See demo

Explanation:

• [ ]* - Optional space(s)
• @ - A @ symbol
• [^º\\n]* - 0 or more symbols other than º and a line break
• [ ]* - Optional space(s)