如何用引号替换尖括号

Question

I have a lot of source codes need modifying, simply as from

#include <headerA.h>

to

#include "headerA.h"

I've tried some sed, awk commands but not completely sure how to proceed this. I'm working on Ubuntu platform. Any inputs would be greatly appreciated!

Answer 1

This will do it:

sed -i '/^#include/s/[<>]/"/g' filename

The /^#include/ address at the beginning tells sed to perform the substitution only on lines that begin with #include . [<>] is a regular expression that matches eith < or > , they get replaced with " , and the g modifier tells it to replace all the occurrences on the line, not just the first.

Answer 2

First use find with sed and then use mv

find . -name <ol_file_nme> -exec sed 's/[<>]/"/g' '{}' \; -print > <new_file_name>
mv  <new_file_name> <ol_file_nme>

Answer 3

This should edit each file in place:

find . -name '*.[ch]' -exec \
    sed -i 's|^#include[[:blank:]]\{1,\}<\([^>]\{1,\}\)>[[:blank:]]*$|#include "\1"|' '{}' \;

Answer 4

This might work for you:

sed '/#include/y/<>/""/' file

Focus on lines that contain headers and translate ( y/.../.../ ) the required characters.

Answer 5

find /Your/Source/Path \
 -name '*.[ch]' \
 -exec \
    sed -i '/^#include[[:blank:]]/ s/<\([^>]*\)>/"\1"/g' "{}" \
 \;

will change:

• any file with extension .h or .c under /Your/Source/Path
• any surrounding text by <> with same text surrouonding by double quote
  • on line starting by #include

Answer 6

sed -i -E "s/^(#include )[\<]([^\>]+)[\>]/\1\\\"\2\\\"/g" sourcefile.c

or, as we don't need variable substitution inside the rule, with single quotes:

sed -i -E 's/^(#include )[\<]([^\>]+)[\>]$/\1"\2"/g'

Loop through all subdirectories of the working directory looking for *.c and *.h files and replace the angle brackets with quotation marks:

find . \( -name "*.c" -o -name "*.h" \) -print0 | xargs -n1 -0 sed -i -E 's/^(#include )[\<]([^\>]+)[\>]$/\1"\2"/g'