[英]Confusing Error message when using Brew
Every time when I run a brew command, it will give me several error lines at the beginning. 每次我运行brew命令时,它都会在开始时给我几行错误。 I can't understand what's going on here. 我不明白这里发生了什么。 Can anyone tell me how I can get rid of the error? 谁能告诉我如何摆脱错误?
brew
/bin/sh: __rvm_ruby_string_find: line 8: syntax error near unexpected token `('
/bin/sh: __rvm_ruby_string_find: line 8: ` ruby-+([1-9]) | ruby-+([1-9]).+([0-9]) | ruby-1.+([1-9]).+([0-9]) | jruby-[19]*)'
/bin/sh: error importing function definition for `__rvm_ruby_string_find'
/bin/sh: __rvm_project_ruby_env_load_parse_file: line 9: syntax error near unexpected token `('
/bin/sh: __rvm_project_ruby_env_load_parse_file: line 9: ` __rvm_read_lines __variables <( { cat "$1"; echo ""; } | __rvm_sed "${__sed_commands[@]}" )'
/bin/sh: error importing function definition for `__rvm_project_ruby_env_load_parse_file'
/bin/sh: __rvm_remove_without_gems: line 2: syntax error near unexpected token `('
/bin/sh: __rvm_remove_without_gems: line 2: ` __rvm_read_lines __gems_to_remove <('
/bin/sh: error importing function definition for `__rvm_remove_without_gems'
Now I found if I run an illegal command for ruby, it gives me a same error message. 现在,我发现如果我对Ruby运行非法命令,它会给我同样的错误消息。 So is it because my version problem? 那是因为我的版本问题吗?
I've had this error due to RVM being source'ed during bash profile setup. 由于在bash配置文件设置过程中来源了RVM,我遇到了此错误。 It seems the RVM script cannot handle being sourced multiple times into the same shell. 看来RVM脚本无法处理多次被提供到同一shell中的情况。
This was being triggered by commands like ssh-agent
, which spawn a new sub-shell, or simply running bash
again. 这是由诸如ssh-agent
类的命令触发的,它会生成一个新的子shell,或者只是再次运行bash
。
My solution was to wrap the RVM source'ing in my .bashrc
with a check for the $rvm_version
variable: 我的解决方案是使用$rvm_version
变量检查将RVM源代码包装在.bashrc
:
if [ -z "$rvm_version" ]; then
export PATH="$PATH:$HOME/.rvm/bin" # Add RVM to PATH for scripting
[[ -s "$HOME/.rvm/scripts/rvm" ]] && source "$HOME/.rvm/scripts/rvm" # Load RVM into a shell session *as a function*
fi
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