根据日期条件返回匹配项的数组公式

Question

The following codes works great for me when my data is stored in row 2 and below. But if my array range is from row 6 and below, how do I adapt the formula? Thanks in advance

=IF(ISERROR(INDEX(Array_Range,SMALL(IF(Health_Check_Date<DATE(YEAR(TODAY())-2,MONTH(TODAY()),DAY(TODAY())),ROW(Health_Check_Date)),ROW($1:$1)),1)),"",INDEX(Array_Range,SMALL(IF(Health_Check_Date<=DATE(YEAR(TODAY())-2,MONTH(TODAY()),DAY(TODAY())),ROW(Health_Check_Date)),ROW($1:$1)),1))

Named Ranges: Array_Range = $A$6:$B$9 Health_Check_Date = B$6$:$B$9

Sample Data (From row 5 onwards)

A       B
Test1   18/05/2015
Test2   15/05/2015
Test3   19/05/1991
Test4   18/05/2013

Answer 1

When your data started in row 2, you were actually offsetting by one row down. This problem was magnified when you shifted the data down to start in row 6. This is due to the difference of returning the worksheet row and the row position within a named range. If Health_Check_Date refers to B6:B9 then wrapping the ROW function around a match on the first row is going to return a 6 , not a 1 . You need to adjust hte return by the starting row of Health_Check_Date .

Your formula was designed to return the first, second, third, etc matches into successive row but you had locked this out with the absolute addresses in ROW($1:$1) . I've removed that restriction.

The EDATE function is a more efficient way to knock a couple years off today.

The IFERROR function reduces the doubling up of the formula that an IF(ISERROR(... requires by evaluating the formula and returning the default if it is in error ot the formula's result if it is not.

The array formula in D1 is,

=IFERROR(INDEX(Array_Range, SMALL(IF(Health_Check_Date<EDATE(TODAY(), -24), ROW(Health_Check_Date)-ROW(INDEX(Health_Check_Date, 1, 1))+1), ROW(1:1)), 1), "")

If blank cells in Health_Check_Date need to be discarded, stack an extra IF into the works that ignores zero length.

=IFERROR(INDEX(Array_Range, SMALL(IF(LEN(Health_Check_Date), IF(Health_Check_Date<EDATE(TODAY(), -24), ROW(Health_Check_Date)-ROW(INDEX(Health_Check_Date, 1, 1))+1)), ROW(1:1)), 1), "")

Array formulas need to be finalized with Ctrl + Shift + Enter↵ (but you knew that!). Fill down for subsequent returns.