如何使用 JavaScript 打印 PHP 变量
[英]How I can print PHP variable using JavaScript
问题描述
I'm trying to print my PHP variable:
我正在尝试打印我的 PHP 变量：
<?php
$section= $_GET['section'];
$author = $_GET['author'];
?>
<html>
<!--Some HTML page's elements-->
</html>
And my JavaScript code:还有我的 JavaScript 代码：
$(document).ready(function(){
var SECTION = '<?php echo $section;?>';
alert('My section is: ' + SECTION);
var AUTHOR = '<?php echo $author;?>';
alert('Current author is: ' + AUTHOR);
});
But only I get in alert's message: 'My section is: ' + <?php echo $section;?> '但只有我收到警报的消息：'我的部分是：' + <?php echo $section;?> '
2 个解决方案
解决方案1
2 已采纳 2015-05-21 19:55:00
Try running this all a single page尝试在一个页面上运行所有这些
test.php?section=5&author=james test.php?section=5&author=james
test.php测试文件
<?php
$section= $_GET['section'];
$author = $_GET['author'];
?>
<html>
<!--Some HTML page's elements-->
</html>
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
var SECTION = '<?php echo $section;?>';
alert('My section is: ' + SECTION);
var AUTHOR = '<?php echo $author;?>';
alert('Current author is: ' + AUTHOR);
});
</script>
works fine工作正常
解决方案2
0 2015-05-21 20:11:14
The answer provided by Rob will set your JS variables from PHP, but also makes you vulnerable to Javascript injection - Do not use this method as is. Rob 提供的答案将从 PHP 设置您的 JS 变量，但也会使您容易受到 Javascript 注入的影响 -不要按原样使用此方法。
If you want to set JS variables from within PHP, and those variables should be set by the user - simply set them from within JS, or do a very strict input filtering.如果您想从 PHP 内部设置 JS 变量，并且这些变量应该由用户设置 - 只需从 JS 内部设置它们，或者进行非常严格的输入过滤。
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.