通过在pentaho中搜索字符串从目录中获取文件名

Question

I am going to prepare a job that has fields such as Path(DIRECTORY) and FileName. These fields value will change for every row.

Objective of my task is, I need to check whether the FileName file exists in the directory. That I did with the "File Exists" step and checked whether file exists. Then I used the "Filter Rows" step and performed an operation if the file exists.

If the file is not present in the directory, I need to check for the other files that starts with the filename value.

Example: I have the file name as "sample.png", if the file does not exists in the directory I want to search for the files that starts with "sample..."(Eg: sample_1.png).

Answer 1

Can you try the approach to

1. fetch the list of files having sample key in the directory using wildcard expression ^sample.* in the " Get File Names " (use a ktr)

2. Then use a filter row step to filter out the two path. True path will pass the data having the filename sample.png and the False path will pass on the files incase sample.png is not found.

A sample image of the ktr would be like

My idea is to read all the files first from the path and then filter out whatever files are required, instead of double checking the existance of the files.

NB In the image above, path is the location of the image directory. Use your own folder path to get the correct result.

Hope it helps:)