与CURL一起使用，如何格式化Postman / REST客户端

Question

I'm sure this is a dumb question but I haven't been able to see the light.

If I have a curl command ...

curl -v  -F "dataType=dws" -F "format=csv" -F "compression=gzip" -F "sha256sum=17685b28be3af7b71bcab78c0393d548d7cd563f3fd5d955309c9512a4ad28ad" -F "file=@/Users/xxx/sql/file.gz" http://localhost:8080/p20/fileUpload

that works perfectly, how do I do the same thing via Postman(or any REST client) ?

Thanks in advance for enlightening me.

Answer 1

tF means Formdata. Normally used for the data from the form fields of a HTML page, which are typically submitted by an POST Request to the server. Curl builds a data string and send it in the body of the HTTP request. An equivalent to your curl statement is:

curl -v -X POST -d "dataType=dws&format=csv&compression=gzip&sha256sum=17685b28be3af7b71bcab78c0393d548d7cd563f3fd5d955309c9512a4ad28ad&file=@/Users/xxx/sql/file.gz" http://localhost:8080/p20/fileUpload

curl treats the file=@... as a special command. It reads the file and appends the content to the body. It also set the mime type to multipart/formdata .

Thats all you must do in postman or equivalent. Enter the string after -d in the body/content field. Set the method to POST. Enter the URL.

-v increases the verbosity level. I don't know how to make postman more verbose.

Answer 2

There is an excellent blog post on Postman.com that gives detailed step by step instructions to turn on verbose mode in postman application. This allows you to observe raw HTTP requests and also do much more debugging.