通过bash脚本运行时，Nodejs process.argv [2]会在空格后甚至\\省略数据

Question

So I have a node script that takes an argument, if I run the node script alone then something like game\\ of\\ thrones the entire string is considered process.argv[2] which is what I wanted and expected, the problem is when I run a very small bash script called add which consists of

#!/bin/bash

echo `nodejs ~/Codes/localHost/node/headsUp/add.js $1`

and then run ./add game\\ of\\ thrones now process.argv[2] is only game why is this? if at all possible I would love to have a solution that allows me to put spaces between arguments to have multiple arguments rather than use something like $@ . Thanks in advance. Oh and when I echo $1 in the bash script it does come up as the full game of thrones .

Answer 1

When you fail to quote $1 , you are telling bash to resplit the parameter into words. In order to pass $1 (or any other parameter or variable) verbatim into another script or binary, you need to make sure it is quoted:

echo `nodejs ~/Codes/localHost/node/headsUp/add.js "$1"`

Note that the output from nodejs will also be word-split, since it is not quoted. If you wanted to preserve formatting (such as newlines), you would need to quote that as well:

echo "$(nodejs ~/Codes/localHost/node/headsUp/add.js "$1")"

Here I changed the deprecated backtick syntax into the recommended $(...) syntax, which nests better.

Answer 2

It feels very 'workaroundish' which makes me feel like there is a better way but for those who may need to have this working you can concatenate your process.argv variable. using this method you can run your script and give it multiple arguments separated by spaces (actual spaces not spaces prefaced with \\ )

function conCatArgs(input){
var args = [];
for(i = 0; process.argv.length - 2 > i; i++){
    args[i] = input[i + 2]
}
console.log(args);
}

conCatArgs(process.argv);