如何通过使用Gremlin在图中通过公共同级对不同父级的所有同级节点进行分组

Question

It is difficult for me to describe. The Gremlin query I am trying to write has one node as an input. Then I am searching all the nodes with class Group of input. Then in each group there is only one Text class node and a number of Elem nodes. I would like to get all the Elem nodes that have as a sibling the same Text node even if they are from different Group nodes. You see the different color of groupings.

Here is what I mean:

What I have so far:

g = new OrientGraph("remote:localhost/graphdb")
v = g.v('#12:109')
v.bothE.has('@class','hasElem').outV.has('@class','Group').bothE.or(_().has('@class','hasText'), _().has('@class','hasElem').except([v])).inV().except([v])

This returns to me all the green and blue nodes together, but I don't know how to do the grouping.

Any help is appreciated :)

Thanks!

Answer 1

It took 5hours but I found the query that does it:

The groupBy mapping basically takes as a key the Text node {it} and as a value the leaf from text->parent->sibling {it.inE.outV.outE.inV.hasNot('@class','Text').except([v])} that is not of class Text except for the Input. The last line m.sort{a,b -> b.value.size() <=> a.value.size()} is sorting Texts in descending popularity, or in other words the ones that have the longer list of related siblings are coming first.

g = new OrientGraph("remote:localhost/graphdb")
v = g.v('#12:109')
m = [:]  
v.bothE.has('@class','hasElem').outV.has('@class','hasElem').dedup().bothE.has('@class','hasText').inV().groupBy(m){it}{it.inE.outV.outE.inV.hasNot('@class','Text').except([v])}
m.sort{a,b -> b.value.size() <=> a.value.size()}