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根据SizeMode转换PictureBox选择矩形

[英]Convert PictureBox Selection Rectangle according to SizeMode

I have two PictureBoxes pbOriginal and pbFace. 我有两个PictureBoxes pbOriginal和pbFace。 After Selecting a "face" from an image in pbOriginal I clone the rectangle selection and place it into pbFace. 从pbOriginal中的图像中选择“面部”后,我克隆矩形选择并将其放入pbFace中。 However, Because pbOriginal is using SelectionMode=Stretch the actual area being copied is not the same as the area being selected. 但是,由于pbOriginal使用的是SelectionMode=Stretch因此实际复制的区域与所选区域不同。

How do I convert the coordinates of the Rectangle so that they truly reflect the coordinates of the Stretched Image? 如何转换矩形的坐标,以使其真正反映拉伸图像的坐标?

Here is an example that draws the second rectangle right along as you draw the first one..: 这是一个示例,它在绘制第一个矩形的同时向右绘制第二个矩形:

在此处输入图片说明

Point mDown = Point.Empty;
Point mCurr = Point.Empty;

private void pictureBox1_MouseDown(object sender, MouseEventArgs e)
{   mDown = e.Location;  }

private void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
    if (e.Button == System.Windows.Forms.MouseButtons.Left)
       { mCurr = e.Location; pictureBox1.Invalidate(); }
}

private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
    Rectangle r = new Rectangle(mDown.X, mDown.Y, mCurr.X - mDown.X, mCurr.Y - mDown.Y);
    e.Graphics.DrawRectangle(Pens.Orange, r);
    pictureBox2.Invalidate();
}

private void pictureBox2_Paint(object sender, PaintEventArgs e)
{
    if (pictureBox2.Image == null) return;

    float stretch1X = 1f * pictureBox1.Image.Width / pictureBox1.ClientSize.Width;
    float stretch1Y = 1f * pictureBox1.Image.Height / pictureBox1.ClientSize.Height;

    int x = (int)(mDown.X * stretch1X);
    int y = (int)(mDown.Y * stretch1Y);
    int x2 = (int)(mCurr.X * stretch1X);
    int y2 = (int)(mCurr.Y * stretch1Y);

    Rectangle r = new Rectangle(x, y, x2 - x, y2 - y);
    e.Graphics.DrawRectangle(Pens.Orange, r);
}

Note that it assumes that you are drawing top-left to bottom-right.. 请注意,它假定您是从左上方绘制到右下方。

If you want to copy the selection you can use the same factors and the same Rectangle as the source for a DrawImage call: 如果要复制选择,则可以使用与DrawImage调用的源相同的因子和相同的Rectangle

float stretch1X = 1f * pictureBox1.Image.Width / pictureBox1.ClientSize.Width;
float stretch1Y = 1f * pictureBox1.Image.Height / pictureBox1.ClientSize.Height;

Point pt = new Point((int)(mDown.X * stretch1X), (int)(mDown.Y * stretch1Y));
Size sz = new Size((int)((mCurr.X - mDown.X) * stretch1X), 
                   (int)((mCurr.Y - mDown.Y) * stretch1Y));


Rectangle rSrc = new Rectangle(pt, sz);
Rectangle rDest= new Rectangle(Point.Empty, sz);

Bitmap bmp = new Bitmap(sz.Width, sz.Height);
using (Graphics G = Graphics.FromImage(bmp))
    G.DrawImage(pictureBox1.Image, rDest, rSrc , GraphicsUnit.Pixel);
pictureBox2.Image = bmp;

You may want to code the MouseUp event to store the finla mCurr position and trgger the copying.. 您可能需要对MouseUp事件进行编码,以存储finla mCurr位置并触发复制。

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