[英]Java CURL request using HTTP
I am trying to perform a CURL request using Java. 我正在尝试使用Java执行CURL请求。 The CURL request is as follows:
CURL请求如下:
curl https://apis.sen.se/v2/feeds/N4hSBSpFlYzXT6ZN2IA1KadgSR9rTazv/events/?limit=1 -u username:password
I am trying to perform the request as follows: 我正在尝试执行以下请求:
String stringUrl = "https://apis.sen.se/v2/feeds/N4hSBSpFlYzXT6ZN2IA1KadgSR9rTazv/events/?limit=1";
URL url = new URL(stringUrl);
URLConnection uc = url.openConnection();
uc.setRequestProperty("X-Requested-With", "Curl");
String userpass = "username" + ":" + "password";
String basicAuth = "Basic " + new String(new Base64().encode(userpass.getBytes()));
uc.setRequestProperty("Authorization", basicAuth);
InputStreamReader inputStreamReader = new InputStreamReader(uc.getInputStream());
and I am trying to see the contents of inputStreamReader
as follows: 并且我试图查看
inputStreamReader
的内容,如下所示:
int data = inputStreamReader.read();
char aChar = (char) data;
System.out.println(aChar);
The code is compiling and running fine, but it is returning nothing. 代码正在编译并且可以正常运行,但是什么也不返回。 Where am I going wrong?
我要去哪里错了?
I ended up getting it working using the following code: 我最终使用以下代码使其工作:
public static void main(String args[]) throws IOException {
String stringUrl = "url";
URL url = new URL(stringUrl);
URLConnection uc = url.openConnection();
uc.setRequestProperty("X-Requested-With", "Curl");
String userpass = "username" + ":" + "password";
String basicAuth = "Basic " + new String(new Base64().encode(userpass.getBytes()));
uc.setRequestProperty("Authorization", basicAuth);
StringBuilder html = new StringBuilder();
BufferedReader input = null;
try {
input = new BufferedReader(new InputStreamReader(uc.getInputStream()));
String htmlLine;
while ((htmlLine = input.readLine()) != null) {
html.append(htmlLine);
}
}
catch (IOException e) {
e.printStackTrace();
}
finally {
try {
input.close();
}
catch (IOException e) {
e.printStackTrace();
}
}
System.out.println(html.toString());
}
I was also trying to do that thing. 我也在尝试做那件事。 I have some kind of workaround but it reads everything it sees.
我有某种解决方法,但它会读取所看到的所有内容。
--Here's the code--- -这是代码-
String params = "some-parameters";
URL url = new URL("some-website");
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setRequestMethod("POST");
con.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(params);
wr.flush();
wr.close();
con.getResponseCode();
BufferedReader reader = new BufferedReader(new InputStreamReader(con.getInputStream()));
String line;
StringBuffer buffer = new StringBuffer();
while((line = reader.readLine()) != null) {
buffer.append(line+"\n");
}
reader.close();
System.out.print(buffer.toString());
--Notice, I use this code to see if a certain account exist on a certain website, since it outputs everything, what I do is to find a specific regularity upon the code which could tell me if that user exist or not. -注意,我使用此代码来查看某个帐户是否存在于某个网站上,因为它会输出所有内容,所以我要做的是在代码上找到特定的规律性,该规则可以告诉我该用户是否存在。 Well I'm not really even sure if this could help you, but it might be.
好吧,我什至不确定这是否能帮到您,但可能会。 Good Luck...
祝好运...
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