带有sed shell脚本的正则表达式

Question

I have a problem when I'm trying to regex a line in a document with sed. Here is what I want to regex:

proxy_pass http:\\\\193.168.19.35/;

I want to obtain the following result:

proxy_pass http:\\\\193.168.19.32/;

This is what I have tried:

sed -r 's/^proxy_pass htpp\:\/\/[[:digit:]]+.*\/;/proxy_pass htpp\:\/\/192.168.81.29\/;/' /etc/nginx/nginx.conf > /etc/nginx/nginx.conf.temp

Can you guys help me here?

Answer 1

If you have a URL with \\\\ , you need to add support for this pattern in your regex. I believe you just misspelt some words in your question.

So, if you want to match proxy_pass http:\\\\193.168.19.32/; , use

sed -r 's/^proxy_pass http\:\\\\[[:digit:]]+(\.[[:digit:]]+)*\/;/proxy_pass htpp\:\/\/192.168.81.29\/;/' /etc/nginx/nginx.conf > /etc/nginx/nginx.conf.temp
                            ^^^^            |---------------|

If you want to replace proxy_pass http://193.168.19.32/; , use

sed -r 's/^proxy_pass http\:\/\/[[:digit:]]+(\.[[:digit:]]+)*\/;/proxy_pass htpp\:\/\/192.168.81.29\/;/' /etc/nginx/nginx.conf > /etc/nginx/nginx.conf.temp
                            ^  ^            |---------------|

Pay attention to (\\.[[:digit:]]+)* in the pattern, it makes it possible to match all the 4 parts of the IP address.