向我的python twitter bot添加一会儿语句

Question

I'm working on a python twitter script. So far it works great, but I need to add a while statement to limit the number of unfollows (api calls) to less than 100. I have been working on this all day and I admit I'm new to python, I may be missing something simple but I have tried a handful of variations to no avail.

#! /usr/bin/python
# -*- coding: utf-8 -*-

import tweepy
from keys import keys

SCREEN_NAME = keys['screen_name']
CONSUMER_KEY = keys['consumer_key']
CONSUMER_SECRET = keys['consumer_secret']
ACCESS_TOKEN = keys['access_token']
ACCESS_TOKEN_SECRET = keys['access_token_secret']
auth = tweepy.OAuthHandler(CONSUMER_KEY, CONSUMER_SECRET)
auth.set_access_token(ACCESS_TOKEN, ACCESS_TOKEN_SECRET)
api = tweepy.API(auth)
followers = api.followers_ids(SCREEN_NAME)
friends = api.friends_ids(SCREEN_NAME)
for f in friends:
    if f not in followers:
        print "Unfollow {0}?".format(api.get_user(f).screen_name)
if raw_input("Y/N?") == 'y' or 'Y':
    api.destroy_friendship(f)

Answer 1

Add an unfollow counter and increment that counter when you make an unfollow call. Then check if the counter is less than 100 in addition to the 'y' answer.

#! /usr/bin/python
# -*- coding: utf-8 -*-

...code before for loop here...
unfollows = 0
for f in friends:
    if f not in followers:
        print "Unfollow {0}?".format(api.get_user(f).screen_name)
        input = raw_input("Y/N?")
        if (unfollows < 100) and (input == 'y' or input 'Y'):
            api.destroy_friendship(f)
            unfollows += 1