[英]How to get the page based on the selection in a drop down list in Django
I'm a new on Django. 我是Django的新手。 One question confused me about the drop down list in Django.
一个问题使我对Django中的下拉列表感到困惑。 I'd like to know how to change the content in a page based on the selection in the drop down list in Django.
我想知道如何根据Django下拉列表中的选择更改页面中的内容。
In Model.py I design the fields as: 在Model.py中,我将字段设计为:
STATUS_IN_CHOICE = (
('Pending','Pending'),
('Passed','Passed'),
('Failed','Failed'),
)
Status = models.CharField(max_length=10,choices=STATUS_IN_CHOICE,
default='Pending')
The respected result I want is, if I select "Passed" in the drop down list. 我想要的受尊敬的结果是,如果我在下拉列表中选择“通过”。 All the passed cases show in the page.
所有通过的案例都显示在页面中。 Others are the same.
其他都一样。
I have no idea how to code the template and connect with the field now. 我不知道如何编码模板并立即与该领域联系。 Cause in my opinion, it's not a forms (post) at all.
我认为,这根本不是表格(帖子)。
You have basically two alternatives, and both of involve the use of javascript. 您基本上有两种选择,并且都涉及使用javascript。
You either: 您要么:
Neither of the above the use of a model if the drop-down is for display filter only, and no storing is required. 如果下拉列表仅用于显示过滤器,并且不需要存储,则以上两种方法都不使用模型。 You could achieve the same with a simple django form or plain HTML.
您可以使用简单的Django表单或纯HTML实现相同的功能。
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