实现可扩展的接口

Question

So I have an interface Foo is constructed like:

public interface Foo<T extends Comparable<? super T>>

and I'm trying to implement Foo in my class bar like:

public class Bar<T> implements Foo<T>

but I get getting the error type argument T#1 is not within bounds of type-variable T#2

but when I try to implement Foo as:

public class Bar<T> implements Foo<T extends Comparable<? super T>>

I get > expected and <identifier> expected

Answer 1

Your syntax is a bit off. Try moving the bounds to the declaration of T as in this:

public class Bar<T extends Comparable<? super T>> implements Foo<T> {
    ...
}