[英]Transfer of image over network via TCP Socket in JAVA isn't working?
I have the following code. 我有以下代码。 It seems that I am streaming the content accurately.
看来我正在准确地传输内容。 However, the image is not being captured correctly.
但是,无法正确捕获图像。 I am new to Java.
我是Java新手。 Basically, I am a C, C++, linux programmer.
基本上,我是C,C ++,Linux程序员。 I am wondering that the problem is reading the buffer line by line.
我想知道问题是逐行读取缓冲区。 Am I missing something here?
我在这里想念什么吗?
Here is the socket server code - 这是套接字服务器代码-
import java.io.*;
import java.net.*;
public class ImageSocketServer {
public static void main(String args[]) throws IOException
{
ImageSocketServer imageServer = new ImageSocketServer();
imageServer.run();
}
private void run() throws IOException {
// TODO Auto-generated method stub
ServerSocket serverSock = new ServerSocket(1025);
Socket sock = serverSock.accept();
InputStream imagetoShare = new BufferedInputStream(new FileInputStream("/export/home/joshis1/Lizard.png"));
PrintStream imageSend = new PrintStream( sock.getOutputStream());
imageSend.print(imagetoShare);
}
}
Here is the socket client code - 这是套接字客户端代码-
import java.io.*;
import java.net.*;
public class ImageSocketClient {
public static void main(String args[]) throws IOException
{
ImageSocketClient imageClient = new ImageSocketClient();
ImageSocketClient.run();
}
private static void run() throws UnknownHostException, IOException
{
// TODO Auto-generated method stub
BufferedWriter bufWriter = null;
bufWriter = new BufferedWriter(new FileWriter(
"/export/home/joshis1/file1.png"));
Socket sock = new Socket("localhost", 1025);
InputStreamReader IR = new InputStreamReader(sock.getInputStream());
BufferedReader BR = new BufferedReader(IR);
String data;
while ((data = BR.readLine()) != null)
{
System.out.println("Shreyas got the data");
bufWriter.write(data);
}
bufWriter.close();
}
}
I see that the source image is of size - 我看到原始图片的大小-
$ ls -l Lizard.png
-rw-rw-r-- 1 joshis1 joshis1 19071522 May 29 15:46 Lizard.png
and the destination image is wrongly copied -
$ ls -l file1.png
-rw-rw-r-- 1 joshis1 joshis1 34 May 29 17:38 file1.png
First of all your imageSend.print(imagetoShare);
首先,您的
imageSend.print(imagetoShare);
sends over the String representation of an InputStream
, which explains the small content of the file. 发送一个
InputStream
的String表示形式,它解释了文件的小内容。 You'll want to create a loop that reads from imagetoShare
(although you might want to name it better, it's not an image, it's a stream) and writes the data to the outputstream (search around for the quintessential read-write loop). 您将需要创建一个从
imagetoShare
读取的循环(尽管您可能想更好地命名它,但它不是图像,而是流),然后将数据写入到输出流中(搜索典型的读写循环)。
Secondly, you're using PrintStream
which is used to write character data to an OutputStream
. 其次,您使用的是
PrintStream
,它用于将字符数据写入OutputStream
。 You want to use a BufferedOutputStream
for that. 您要为此使用
BufferedOutputStream
。
There's a variety of errors in your code due to wrong use of the various java.io
-classes. 由于对各种
java.io
-class的错误使用,代码中会出现各种错误。
1.) You are using PrintStream
's print(Object o)
method. 1.)您正在使用
PrintStream
的print(Object o)
方法。 This is not copying the stream's content but is just writing a textual representation of the object. 这不是复制流的内容,而只是编写对象的文本表示形式。
2.) In your client you are using Reader
and Writer
classes. 2)在您的客户端中,您使用的是
Reader
和Writer
类。 These are used to handle character-data while your images are raw binary data. 这些用于处理字符数据,而图像是原始二进制数据。 You'll get into lots of trouble considering encoding, non-printable characters etc. this way.
这样,考虑编码,不可打印的字符等会遇到很多麻烦。
To wrap it up: Use plain BufferedInputStream
s and BufferedOutputStream
s to do your input and output. 总结:使用普通的
BufferedInputStream
和BufferedOutputStream
进行输入和输出。 You'll have to wrap it all up in some loops because you'll only be reading a bunch of bytes at a time. 您必须将其全部包装成一些循环,因为您一次只能读取一堆字节。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.