[英]Try - Catch in if - else if instruction
I was able to implement the function of the try - catch for the variable choice and it works great. 我能够实现try的功能-捕获变量选择,效果很好。 I have a problem with variable stopnie.
我有可变的stopnie问题。 I want to check if this is numerical value.
我想检查一下这是否是数值。 I tried to throw it in the try catch, unfortunately without success
不幸的是,我试图将其扔到尝试捕获中
class Task {
public static void main(String[] args) {
Scanner user_input = new Scanner (System.in);
System.out.println("Pick 1 to convert Fahrenheit to Celsius");
System.out.println("Pick 2 to convert Ceslius to Fahrenheit");
int choice = 0;
double stopnie = 0.0;
double convert = 0.0;
DecimalFormat df = new DecimalFormat("0.00", new DecimalFormatSymbols(Locale.US));
boolean loop = true;
while (loop)
{
try
{
choice = user_input.nextInt();
loop = false;
}
catch (Exception e)
{
System.out.println("Bad value");
System.out.println("Try again");
user_input.next();
}
}
if(choice == 1)
{
System.out.println("Let me know Celsius value");
stopnie = user_input.nextDouble();
convert = stopnie/1.8-35;
System.out.println(stopnie + " C " + " = " + df.format(convert) + " F");
}
else if (choice == 2)
{
System.out.println("Let me know Fahrenheit value");
stopnie = user_input.nextDouble();
convert = stopnie*1.8+35;
System.out.println(stopnie + " F " + " = " + convert + " C");
}
else
{
System.out.println("Bad value");
}
}
}
so, I added try catch to if(choice == 1): with while loop 所以,我添加了try catch到if(choice == 1):with while循环
if(choice == 1)
{
while (loop)
{
try {
System.out.println("Let me know Celsius value");
stopnie = user_input.nextDouble();
convert = stopnie/1.8-35;
System.out.println(stopnie + " C " + " = " + df.format(convert) + " F");
} catch (Exception e) {
System.out.println("Bad value");
System.out.println("Try again");
user_input.next();
}
}
}
Now, when I start program and Pick 1 nothing happens. 现在,当我启动程序并选择1时,什么都没有发生。 I want to pick 1, go to function if(chooice ==1) and if there will be any error print Bad value, try again and add input to put value again
我想选择1,转到函数if(chooice == 1),如果出现任何错误打印错误值,请重试并再次添加输入到put值
try this code: 试试这个代码:
public static void main(String[] args) {
Scanner user_input = new Scanner (System.in);
try {
int f=user_input.nextInt();
System.out.println("It's an Integer");
} catch (InputMismatchException e) {
System.out.println("It's not Integer");
// Should print the exception
//e.printStackTrace();
}
}
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