Java：用户输入Antilog Base问题？

Question

I'm finding anti-logarithm of enter values.Answer will be right with natural log base.But when try to find anti-log with enter base.then it doesn't give correct answer such as
anti-log value 10 with base 10 = 10000000000
This is my code:

    public class A {

public static void main(String[] args) {
    Scanner s = new Scanner(System. in );
    double value, res, value2, res2;
    System.out.print("Enter Anti Log Value:");
    value = s.nextDouble();
    res = Math.exp(value);
    System.out.println("Answer Of Antilog With natural Base is: + res);
    System.out.println("-----------------------------------");
    System.out.print("Enter Your Base:");
    value2 = s.nextDouble();
    res2 = Math.exp(value) / Math.exp(value2);
    System.out.println("Answer Of Antilog With your enter Base is : " + res2);
}
}

It give answer with enter base 10 = 1.0 so how to fix this.

Answer 1

Assuming I understand your question correct you should simply replace

res2 = Math.exp(value) / Math.exp(value2);

with

res2 = Math.pow(value2, value);

If you want to avoid scientific notation when printing the value, use:

System.out.printf("Answer Of Antilog With your enter Base is : %f%n", res2 );

or (to skip the decimals):

System.out.printf("Answer Of Antilog With your enter Base is : %.0f%n", res2 );