无法显示来自MySQL的图像

Question

I am unable to display images from MySQL. I've checked path etc. but still there are broken images on site. Below is my Code. Please guide me.

<div id="right_content">
    <div id="headline">
    <div id="headline_content"> <b>Welcome Guest!</b> <b style="color:#F56013">Shopping Cart</b> <span>-Items: -Price: </span> </div>
</div>
<div id="products_box">
    <?php
        $get_products ="SELECT * FROM products ORDER BY rand() LIMIT 0,6";

        $run_products = mysqli_query($con,$get_products);

        while($row_products=mysqli_fetch_array($run_products)){
            $prod_id = $row_products['product_ID'];
            $prod_title = $row_products['product_title'];
            $prod_cat = $row_products['category_ID'];
            $prod_brand = $row_products['brand_ID'];
            $prod_price = $row_products['product_price'];
            $prod_desc = $row_products['product_desc'];
            $prod_img =$row_products['product_img1'];



            echo "
            <div id='single_product'>
            <h3>$prod_title</h3>
            <img src='admin_area/product_images/$prod_img' width='180' height='180' />
            </div>
            ";
        }
        ?>
</div>

Answer 1

As per comment, problem is solved. The images were not moving into the directory and i didn't check that. When i manually copied them into the specified directory the problem was gone.

Answer 2

When you write html please note that you should always use double and not single quotes for tag properties. So for example

src='admin_area/product_images/$prod_img'

should be

src="admin_area/product_images/$prod_img"

and so on. Since you are doing echo using double quotes you should escape double quotes with . So your echo should look like:

echo "
    <div id=\"single_product\">
    <h3>$prod_title</h3>
    <img src=\"admin_area/product_images/$prod_img\" width=\"180\" height=\"180\" />
    </div>
";

IMHO it is better to write plain html and use php only to echo variables just to avoid this kind of problems with the generated code. So I'd write:

?>
        <div id="single_product">
        <h3><?php echo $prod_title; ?></h3>
        <img src="admin_area/product_images/<?php echo $prod_img; ?>" width=\"180\" height=\"180\" />
        </div>

<?php } ?>

This will save you a lot of headache in case of debugging if your code is not working