如何获取cookie值
[英]How to get cookie value
问题描述
Creating cookie
创建 cookie
session_start();
$params = session_get_cookie_params();
setcookie(session_name('USERNAME'),'HAMZA',1,
isset($params['path']),
isset($params['domain']),
isset($params['secure']),
isset($params['httponly']));
session_regenerate_id(true);
echo "COOKIE IS CREATED SUCCESSFULLY !";
Now fetching cookie value现在获取 cookie 值
session_start();
$NAME=$_COOKIE['USERNAME'];
echo $_COOKIE["USERNAME"];
if(isset($NAME))
{
if($NAME=='USERNAME')
{
echo "success";
}
else
{
echo "error";
}
}
Please Help Me !请帮我 ！
Result结果
Why they create Auto random Value Like: u8omuum6c9pkngrg4843b3q9m3).为什么他们创建自动随机值，例如：u8omuum6c9pkngrg4843b3q9m3）。 But i want to get my Original COOKIE value Which is "HAMZA" ?????但我想获得我的原始 COOKIE 值，即“HAMZA”？？？？
4 个解决方案
解决方案1
31
This is the PHP syntax for cookie creation:这是创建 cookie 的 PHP 语法：
setcookie($name, $value, $expires, $path, $domain, $secure, $httponly);
The first variable is your cookie name, which you can use to read the value like this:第一个变量是您的 cookie 名称，您可以使用它来读取值，如下所示：
$_COOKIE['YOUR COOKIE NAME'];
Note: Like other headers, cookies must be sent before any output from your script.
<html>and any whitespace.<html>和任何空格）之前调用此函数。
Also note that dots and spaces (././) in cookie names are replaced with underscores (_)._)。
Documentation: setcookie() , $_COOKIE[]文档： setcookie() , $_COOKIE[]
解决方案2
7 2018-06-01 12:15:31
Function session_name will give you hash which atucally is you session identifier.函数 session_name 会给你哈希，这实际上是你的会话标识符。 It seems like you want to get USERNAME stored in session, don't you?您似乎想将 USERNAME 存储在会话中，不是吗？ In that case you should use $_SESSION array.在这种情况下，您应该使用 $_SESSION 数组。
Code example:代码示例：
setcookie($_SESSION['USERNAME'],'HAMZA',1,
isset($params['path']),
isset($params['domain']),
isset($params['secure']),
isset($params['httponly']));
And you can get it like this:你可以这样得到它：
$myCookie = $_COOKIE[$_SESSION['USERNAME']];
But from your second code it's not quite clear what you want to get.但是从你的第二个代码来看，你想得到什么还不是很清楚。 If you want to ask for $_COOKIE['USERNAME'] and get 'HAMZA' then you should set it like this:如果你想询问 $_COOKIE['USERNAME'] 并得到 'HAMZA' 那么你应该这样设置：
setcookie('USERNAME','HAMZA',1,
isset($params['path']),
isset($params['domain']),
isset($params['secure']),
isset($params['httponly']));
And when you retrieve it $NAME=='USERNAME' makes no sense, because it will be like $NAME=='HAMZA':当你检索它时 $NAME=='USERNAME' 没有意义，因为它会像 $NAME=='HAMZA'：
$NAME=$_COOKIE['USERNAME'];
echo $_COOKIE['USERNAME'];
if(isset($NAME))
{
if($NAME=='HAMZA')
{
echo "success";
}
else
{
echo "error";
}
}
解决方案3
0 2021-11-18 04:59:40
try this one ...试试这个...
setcookie($cookie_name, $cookie_value, 1800, "/");
change expires time with:更改过期时间为：
setcookie($cookie_name, $cookie_value, time()+ 1800, "/");
解决方案4
-1 2021-02-19 16:12:16
try this one ...试试这个...
<?
$yummy = json_decode(json_encode($_COOKIE));
if(isset($yummy->yourvar)) echo $yummy->yourvar;
?>
Why using encode and decode ?, it use to convert type Array to JSON originally type $_COOKIE is Array为什么使用编码和解码？，它用于将类型 Array 转换为 JSON 最初类型 $_COOKIE 是 Array
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