使用filter_var验证带和不带协议的URL

Question

I am attempting to validate using PHP's filter_var() extension. Per http://php.net/manual/en/filter.filters.validate.php :

Validates value as URL (according to » http://www.faqs.org/rfcs/rfc2396 ), optionally with required components. Beware a valid URL may not specify the HTTP protocol http:// so further validation may be required to determine the URL uses an expected protocol, eg ssh:// or mailto:. Note that the function will only find ASCII URLs to be valid; internationalized domain names (containing non-ASCII characters) will fail.

In regards to, Beware a valid URL may not specify the HTTP protocol , my tests below indicate that a HTTP protocol is required ( URL 'stackoverflow.com/' is NOT considered valid. ). How am I misinterpreting the documentation?

Also, how are URLs such as https://https://stackoverflow.com/ prevented from validating true?

PS. Any comments on my approach of sanitizing the protocol would be appreciated.

<?php
function filterURL($url) {
    echo("URL '{$url}' is ".(filter_var($url, FILTER_VALIDATE_URL)?'':' NOT ').'considered valid.<br>');
}
function sanitizeURL($url) {
    return (strtolower(substr($url,0,7))=='http://' || strtolower(substr($url,0,8))=='https://')?$url:'http://'.$url;
}

filterURL('http://stackoverflow.com/');
filterURL('https://stackoverflow.com/');
filterURL('//stackoverflow.com/');
filterURL('stackoverflow.com/');
filterURL(sanitizeURL('http://stackoverflow.com/'));
filterURL(sanitizeURL('https://stackoverflow.com/'));
filterURL(sanitizeURL('stackoverflow.com/'));

filterURL('https://https://stackoverflow.com/');
?>

OUTPUT:

URL 'http://stackoverflow.com/' is considered valid.
URL 'https://stackoverflow.com/' is considered valid.
URL '//stackoverflow.com/' is NOT considered valid.
URL 'stackoverflow.com/' is NOT considered valid.
URL 'http://stackoverflow.com/' is considered valid.
URL 'https://stackoverflow.com/' is considered valid.
URL 'http://stackoverflow.com/' is considered valid.
URL 'https://https://stackoverflow.com/' is considered valid.

Answer 1

FILTER_VALIDATE_URL uses parse_url() , which unfortunatelly parses 'https://https://' as a valid URL (as it is really a valid one considering URIs RFC):

var_dump(parse_url('https://https://stackoverflow.com/'));

array(3) { 
  ["scheme"]=> string(5) "https" 
  ["host"]=> string(5) "https"
  ["path"]=> string(20) "//stackoverflow.com/" 
}

You could change your sanitazeURL function into:

function sanitizeURL($url) {
  return (parse_url($url, PHP_URL_SCHEME)) ? $url : 'http://' . $url;
}

but still you have to check whether host name is not http nor https :

function filterURL($url) {
  echo("URL '{$url}' is ".((filter_var($url, FILTER_VALIDATE_URL) !== false && (parse_url($url, PHP_URL_HOST) !== 'http' && parse_url($url, PHP_URL_HOST) !== 'https'))?'':' NOT ').'considered valid.<br>');
}

Answer 2

You can remove the http or add it by validation it exist or not.

<?php
$url = "http://www.nigeriatest.com";

// Remove all illegal characters from a url
$url = filter_var($url, FILTER_SANITIZE_URL);

// Validate url
if (!filter_var($url, FILTER_VALIDATE_URL) === false) {
    echo("$url is a valid URL");
} else {
    echo("$url is not a valid URL");
}
?>

Answer 3

How am I misinterpreting the documentation?

The specification doesn't say anything about not having a protocol - it simply states that the protocol might not be HTTP.

You chop of the important piece of the sentence in your quote...

Beware a valid URL may not specify the HTTP protocol http:// so further validation may be required to determine the URL uses an expected protocol

A protocol is expected , it may or may not be HTTP.