PHP SQL每个代码显示一行

Question

I've written the following code, but I really think it's the wrong way of doing it. Especially if I have more then 5 lines. What I'm trying to achieve is getting all lines from the table and output them one by one. I tried a while loop but the problem is that every block uses different .css classes. I think I'm going wrong in the SQL Query, any sugestions would be appreciated.

The code is :

$image_one_sql = mysql_query("SELECT * FROM {$home_table} WHERE home_id=1"); 
$image_one_row = mysql_fetch_array($image_one_sql);
$image_one = 'data:image/jpeg;base64,' . base64_encode( $image_one_row['data'] ) . '"';

$image_two_sql = mysql_query("SELECT * FROM {$home_table} WHERE home_id=2"); 
$image_two_row = mysql_fetch_array($image_two_sql);
$image_two = 'data:image/jpeg;base64,' . base64_encode( $image_two_row['data'] ) . '"';

Answer 1

    $image_one_sql = mysql_query("SELECT * FROM {$home_table}");
     WHILE ($rows = mysql_fetch_array($image_one_sql)){
    $image[]='data:image/jpeg;base64,' . base64_encode($rows['data'] )
    }
//pr($image);

then using foreach:

foreach($image as $rows_image){
  //Some code
   }