python开发非贪婪正则表达式以匹配特定模式几次

Question

I am about to develop a regex for a pattern given in a file I want to process.

The file contains several articles, which all follow a similar pattern:

1. start with a line ie newline
2. then have some non-word characters on a line followed by "Dokument xx von xx" and a newline
3. that is followed by a body of characters
4. ends with two newlines, followed by a line with non-word characters followed by "Copyright" followed by more characters and a new line
5. one optional line containing non-word characters followed by more characters and a new line
6. finally one line containing non-word characters followed by either "All Rights Reserved" or "Alle Rechte vorbehalten" and a new line

I try to come up with a non-greedy regex, that accurately matches the start, body, and end of the article(s).

For 1-4 I have ^n\\W+Dokument.+?[\\r\\n][\\r\\n]\\W+Copyright[^\\n]+\\n

What is necessary for 5-6?

Do I actually need a dotall flag if I aim to use this regex as proposed to match the pattern several times in a file?

I have been on this all day. Can someone with a fresh mind show me the missing bits?

Cheers, Andrew

Answer 1

You can use the following:

5. one optional line containing non-word characters followed by more characters and a new line

(\W+?(?:(?!All|Alle).)+?\n)?

6. one line containing non-word characters followed by either "All Rights Reserved" or "Alle Rechte vorbehalten" and a new line

\W+(All Rights Reserved|Alle Rechte vorbehalten)\n

Combining 1-6:

^\W+Dokument.+?[\r\n][\r\n]\W+Copyright[^\n]+\n(\W+?(?:(?!All|Alle).)+?\n)?\W+?(?:All Rights Reserved|Alle Rechte vorbehalten)\n

See DEMO