使用正则表达式的Grep文件扩展名

Question

I have filenames for examples as below names

1) "Wireshark-win64-1.12.5.exe" 2) "Service - Document.docx"

Is there anyway I can grep the file extension using some generic regular expression and save it in a xslt variable. I was using some string function as below, but for value such as shown above in 1), it won't work.

<xsl:variable name="fileExtension" select="substring-before(substring-after($filename,'.'),'&quot;')"/>

Answer 1

If you're using XSLT 2.0, then:

tokenize($filename, '\.')[last()]

will extract the file extension from $filename for you.