用Javascript Regex替换不包含特定字符串的行的回车

Question

I have some text line following

Procedure Gato
Do task1
    If early Then come back
    turn 2
End Procedure
Schedule Balo
    If late Then go to home
    turn 2
End Schedule'

The result I need is

Procedure Gato: Do task1: If early Then come back
    turn 2: End Procedure
Schedule Balo: If late Then go to home
    turn 2: End Schedule'

I used pattern \\(?!\\n.*(\\b(Procedure |Schedule |Then )).*)\\n\\ to replace all carriage return not containing "Procedure" or "Schedule" or "Then" before. However it works well for only "Procedure" and "Schedule" not including "Then". How to get the exact result as I need? Glad to receive some advice.

Answer 1

This pattern will do the job:

(^(?:(?!Then)(?! Procedure)(?! Schedule).)*)(\n\s*)

Its basically capturing the lines that don't have the words on the lookAheads and replacing \\n\\s* with the space( \\s* mostly for next line tabs). I captured the group with the rest of the line also so the replacement must be $1:

See Demo

Answer 2

Change:

|Then

to:

|.*Then

or replace the .* with a more restrictive regex. For example:

/(?!\n.*(\b(Procedure |Schedule |.*?Then )).*)\n/g