[英]For…Next loop breaks when using Not() operator
I am running a for...next loop that checking whether entries in a dataset meet a certain condition (in this case IsNA). 我正在运行for ... next循环,以检查数据集中的条目是否满足特定条件(在本例中为IsNA)。 However, changing the if-then-else conditions within this loop to also check whether a condition is not met seems to break the for/next loop. 但是,在此循环中更改if-then-else条件以检查是否不满足条件似乎会破坏for / next循环。 I receive a Next without For error even though that element of the sub hasn't changed. 即使子元素的该元素没有更改,我也会收到一个没有For错误的Next。
I'm lost as to why the it thinks there is no next in the for loop when that part of the code hasn't changed. 我不知道为什么当代码的那部分没有更改时,它认为for循环中没有下一步。
--Original Working Code-- -原始工作守则-
Option Explicit
Dim i As Double
Dim a As Range
Public ssht As Worksheet
Public susht As Worksheet
Public mdsht As Worksheet
Public LastRow As Long
Dim testcell As Long
Public Sub MissingDataSetCopy()
'Part Bii
'Find rows with NA error
Application.ScreenUpdating = False
Dim i, j As Integer
j = 4
'Finds current range on Summary worksheet
Set ssht = ThisWorkbook.Worksheets("sandbox")
Set mdsht = ThisWorkbook.Worksheets("MissingData")
Set susht = ThisWorkbook.Worksheets("summary")
'Copies data to sandbox sheet as values
susht.UsedRange.copy
ssht.Range("A1").PasteSpecial (xlPasteValues)
LastRow = ssht.Range("A4").CurrentRegion.Rows.Count
Dim testcell As Double
Dim numchk As Boolean
'For...Next look call ISNUMBER test
For i = 860 To 874
If Application.WorksheetFunction.IsNA(ssht.Range("B" & i)) Then
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i - 1 & ":G" & i - 1).Value
j = j + 1
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i & ":G" & i).Value
j = j + 1
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i + 1 & ":G" & i + 1).Value
j = j + 1
End If
Next i
Dim fnd As Variant
Dim rplc As Variant
fnd = "#N/A"
rplc = "=NA()"
mdsht.Cells.Replace what:=fnd, Replacement:=rplc, _
LookAt:=xlPart, SearchOrder:=xlByRows, MatchCase:=False, _
SearchFormat:=False, ReplaceFormat:=False
End Sub
--Edit to If Statements-- -编辑为If语句-
For i = 860 To 874
If Application.WorksheetFunction.IsNA(ssht.Range("B" & i)) And Application.WorksheetFunction.IsNA(ssht.Range("B" & i - 1)) Then
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i & ":G" & i).Value
j = j + 1
If Application.WorksheetFunction.IsNA(ssht.Range("B" & i)) And Not (Application.WorksheetFunction.IsNA(ssht.Range("B" & i - 1))) Then
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i - 1 & ":G" & i - 1).Value
j = j + 1
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i & ":G" & i).Value
j = j + 1
End If
Next i
You need to close the second If
block: 您需要关闭第二个If
块:
For i = 860 To 874
If Application.WorksheetFunction.IsNA(ssht.Range("B" & i)) And Application.WorksheetFunction.IsNA(ssht.Range("B" & i - 1)) Then
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i & ":G" & i).Value
j = j + 1
End If '<-- it was not closed
If Application.WorksheetFunction.IsNA(ssht.Range("B" & i)) And Not (Application.WorksheetFunction.IsNA(ssht.Range("B" & i - 1))) Then
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i - 1 & ":G" & i - 1).Value
j = j + 1
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i & ":G" & i).Value
j = j + 1
End If
Next i
Or alternatively using the ElseIf
keyword if the two conditions (at it seems) are excluding each other: 或者,如果两个条件(看起来)彼此排斥,则使用ElseIf
关键字:
For i = 860 To 874
If Application.WorksheetFunction.IsNA(ssht.Range("B" & i)) And Application.WorksheetFunction.IsNA(ssht.Range("B" & i - 1)) Then
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i & ":G" & i).Value
j = j + 1
ElseIf Application.WorksheetFunction.IsNA(ssht.Range("B" & i)) And Not (Application.WorksheetFunction.IsNA(ssht.Range("B" & i - 1))) Then
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i - 1 & ":G" & i - 1).Value
j = j + 1
mdsht.Range("B" & j & ":H" & j).Value = ssht.Range("A" & i & ":G" & i).Value
j = j + 1
End If
Next i
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