[英]SQL query to get columns based on value
I have a table like below 我有一个像下面的桌子
user_id | month, | value
---------+------------+--------
1 | 2013-02-01 | 1
1 | 2013-01-01 | 0
1 | 2013-03-01 | 5
2 | 2013-02-01 | 1
Supposedly a user_id
can not have same month
more than one. 假设一个
user_id
month
不能超过一个。
Let's say I can put the months I want to query in the query statement. 假设我可以将要查询的月份放在查询语句中。 like below
像下面
SELECT user_id, (bla bla bla) AS '2013-03-01', (bla bla bla) AS '2013-02-01'
How do I get a result like below, with minimum number of queries and post-processing (eg using python or php)? 如何获得最少查询和后处理次数(例如,使用python或php)的以下结果?
user_id | 2013-03-01 | 2013-02-01 | 2013-01-01
---------+------------+------------+------------
1 | 5 | 1 | 0
2 | NULL | 1 | NULL
You can use conditional aggregates to get the required result set: 您可以使用条件聚合来获取所需的结果集:
SELECT user_id,
MAX(CASE WHEN month = '2013-03-01' THEN value END) AS '2013-03-01',
MAX(CASE WHEN month = '2013-02-01' THEN value END) AS '2013-02-01',
MAX(CASE WHEN month = '2013-01-01' THEN value END) AS '2013-01-01'
FROM mytable
GROUP BY user_id
This works as long there is a predefined set of month
values. 只要存在一组预定义的
month
值,此方法就起作用。 Otherwise you have to use dynamic SQL. 否则,您必须使用动态SQL。
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