MySQL / PHP背景图片网址2

Question

I have a little problem with a php/sql backgroung-image. My code is

while($row = mysql_fetch_array($result)){
        echo
        '<div>',
            '<div>',
                '<a href="#">',
                '<div class="coupimage" style="background-image: url("'.$row['img_5'].'");"></div></a>',
                '<br />',
                '<h3>'.$row['var1'].'</h3>', '<br />',
                $row['var2'],', ',
                $row['var3'],'<br />',
                $row['var4'],', ',
                $row['var5'], '<br />',
            '</div>',
        '</div>';
}

It work good for each "var" but background-image don't work.

echo $row['img_5'];

print correct link and if I use

'<img src="'.$row['img_5'].'">'

work great too but in style class it return image link without "/" and it don't work.

ex http://www.example.org/image.jpg -> http: www.example.org image.jpg

What I have to do?

Answer 1

Replace space to "/"

// $str == $row['img_5']
// It will work if we got an space

$str = "http: www.example.org image.jpg";

$arr = explode(" ", $str);

$url = $arr[0]."/".$arr[1];

In ur case :

while($row = mysql_fetch_array($result)){
        $arr = explode(" ", $row['img_5']);
        $url = $arr[0]."/".$arr[1];

        echo
        '<div>',
            '<div>',
                '<a href="#">',
                '<div class="coupimage" style="background-image: url("'.$url.'");"></div></a>',
                '<br />',
                '<h3>'.$row['var1'].'</h3>', '<br />',
                $row['var2'],', ',
                $row['var3'],'<br />',
                $row['var4'],', ',
                $row['var5'], '<br />',
            '</div>',
        '</div>';
}