[英]Defining a JS function in PHP
I am Working on a little Webpage, which has a .php-include hierarchy. 我正在研究一个小型网页,该网页具有.php-include层次结构。 Now I want to generate two relying Dropdown-Menues, where the second one is updated, after you choose an option in the first one.
现在,我想生成两个依赖的下拉菜单,在第一个菜单中选择一个选项后,第二个菜单将更新。
I would prefer if the code for this page could stay in one file, as I want to achieve this without splitting the code. 我希望此页面的代码可以保留在一个文件中,因为我想在不拆分代码的情况下实现这一目标。
The code looks something like this: 代码看起来像这样:
<?php
echo '<div id="dashheader">
<form action="..." method="get" enctype="text/plain">
<p id="dashheadline">Selbstkosten ermitteln</p>
..
<td><select name="lieferant" onChange="javascript:updateArtikel(this.value);" >
...
<div id="art">
<select name="artikel">
<option value="">Erst Lieferanten wählen</option>
</select>
</div>';
?>
Now i have the Javascript which I want to be executed on a Change in the "lieferant"-Dropdown(Simple Ajax Call): 现在,我有了要在“ lieferant” -Dropdown(简单Ajax调用)中进行更改时执行的Javascript:
<script type="text/javascript">
function updateArtikel(str) {
...
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("art").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET","cure1.php?q="+str,true);
xmlhttp.send();
...
}
</script>
cure1.php is the same .php-File I generate the Output in. It also contains additional php-Code, in Case it is called with a parameter "q" (see AJAX-Call): curry1.php是我在其中生成输出的.php文件。它还包含其他php代码,以防使用参数“ q”调用它(请参阅AJAX-Call):
if(isset($_GET['q'])){
echo '<select id="art" name="artikel">';
$abfrage = //MYSQL-Query;
$ergebnis = mysqli_query($con,$abfrage);
while($row = mysqli_fetch_object($ergebnis))
{
echo '<option value = "'.$row->PositionsNr.'" > '.$row->Artikelbezeichnung.'</option>';
}
echo '</select>';
}
Now the Question: Is it really possible to leave this code in one File? 现在的问题是:是否真的有可能将此代码保留在一个文件中? If not, How shall I put the code, if the "cure1.php" (my page) is loaded per "index.php?menu=10" ?
如果没有,如果每个“ index.php?menu = 10”加载了“ cure1.php”(我的页面),我该如何放置代码?
see your hierarchy of php file carefully. 仔细查看您的php文件层次结构。 At last code should like
最后代码应该像
<?php
......
//php code
?>
<html>
<head>
<script>
//javascript code
</script>
</head>
</html>
you may also echo all html code within php tags. 您也可以在php标签中回显所有html代码。 This is standard, you may not restricted to do same.
这是标准的,您可能不限于这样做。
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