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替换阵列上的括号

[英]Replace Brackets on Array

I have an array like this: ["one", two"]我有一个这样的数组: ["one", two"]

If I make array.toString().replace("[", "").replace("]", "").trim();如果我制作array.toString().replace("[", "").replace("]", "").trim(); , I will have: "one, two" ,我会有: "one, two"

What I really want is "one", "two"我真正想要的是"one", "two"

How can I do this?我怎样才能做到这一点?

EDIT:编辑:

This is a simple program to explain my question:这是一个简单的程序来解释我的问题:

 ArrayList<String> array = new ArrayList<>();

    array.add("one");
    array.add("two");

    String stringArray = array.toString().replace("[", "").replace("]", "");

    Gson gson = new Gson();
    String json = gson.toJson(stringArray);
    System.out.println(json);

You can try with你可以试试

array.stream().map(s->"\""+s+"\"").collect(Collectors.joining(", "));

which will first surround each strings with quotes, then join them using ,这将首先用引号将每个字符串括起来,然后使用,

For Java 7对于 Java 7

String delimiter = ", ";
StringBuilder sb = new StringBuilder();

if (!array.isEmpty()) {
    sb.append('"').append(array.get(0)).append('"');
}
for (int i = 1; i < array.size(); i++) {
    sb.append(delimiter).append('"').append(array.get(i)).append('"');
}

String result = sb.toString();

Well, just replace comma's with some extra " 's好吧,只需用一些额外的"替换逗号

array.toString().replace("[", "").replace("]", "").trim().replace(", ", "\", \"")

(Not tested, but you get the idea) (未经测试,但你明白了)

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