没有可行的将std :: weak_ptr转换为std :: shared_ptr的方法调用

Question

I am able to convert back and forth inline.

std::shared_ptr<sfg::Notebook> mNotebook = ...;
std::weak_ptr<sfg::Notebook> weakNotebook(mNotebook);
std::shared_ptr<sfg::Notebook> strongNotebook(weakNotebook);

When I attempt to pass it to a method, I get the error:

"No viable conversion between std::weak_ptr<sfg::Notebook> to std::shared_ptr<sfg::Notebook>."

I am calling the method normally, and the method looks like:

onNotebookLeftClick(weakNotebook);

void onNotebookLeftClick(std::shared_ptr<sfg::Notebook> notebook) {
}

I am using OS X (10.10.2).

Answer 1

The shared_ptr constructor you're trying to use is explicit .

template< class Y >
explicit shared_ptr( const std::weak_ptr<Y>& r );

Your first example

std::shared_ptr<sfg::Notebook> strongNotebook(weakNotebook);

works because you're using direct initialization, which works with explicit constructors. You'd have the same problem if you used copy initialization instead

std::shared_ptr<sfg::Notebook> strongNotebook = weakNotebook; // this will fail

---

To fix your error, do one of the following

onNotebookLeftClick(std::shared_ptr<sfg::Notebook>{weakNotebook});

or

onNotebookLeftClick(weakNotebook.lock());

Note that there's a difference between the two methods. If the weak_ptr has expired , the first solution will throw std::bad_weak_ptr , while the second option will construct an empty shared_ptr in that case.