Python计数2变量（如果唯一）

Question

The code has to count the 2 variable if they are unique.
But i cant get it to work.
Does someone have an idea how i can get it to work?

I want the output to be:

C603 100nF 8

Here is a litle example of the .txt file.
BaseBoard_V1.2_Componentlist.txt

C1                      1nF            C0603                 rcl                                    (24.7 35.9)           R270
C2                      100nF          C0603                 rcl                                    (36.7 32.7)           R180
C3                      10uF_Tantalum  C0603                 rcl                                    (22.7 6.45)           R0
C4                      22uF           C0603                 rcl                                    (25 8.25)             R90
C5                      1uF            C0603                 rcl                                    (22.6 21.85)          R180

Code:

from operator import itemgetter
from collections import Counter

elements = []

elements.append([])
elements.append([])
elements.append([])

with open('C:\\Python\\Artinis\\BaseBoard_V1.2_Componentslist.txt') as f:
    for i in xrange(10):
        f.next()
    for line in f:
        list = line.split();
        elements[0].append(list[0])
        elements[1].append(list[1])
        elements[2].append(list[2])

for value, package in sorted(zip(elements[1], elements[2])):
    input = value, package
    c = Counter( input )
    print ( c.items() )

Output:

[('0.22uF', 1), ('C0603', 1)]
[('100', 1), ('R0603', 1)]
[('100', 1), ('R0603', 1)]
[('100', 1), ('R0603', 1)]
[('100', 1), ('R0603', 1)]
[('C0603', 1), ('100nF', 1)]
[('C0603', 1), ('100nF', 1)]
[('C0603', 1), ('100nF', 1)]
[('C0603', 1), ('100nF', 1)]
[('C0603', 1), ('100nF', 1)]
[('C0603', 1), ('100nF', 1)]
[('C0603', 1), ('100nF', 1)]
[('C0603', 1), ('100nF', 1)]
[('10K', 1), ('R0603', 1)]
[('10K', 1), ('R0603', 1)]
[('10k', 1), ('R0603', 1)]
[('10uF_Tantalum', 1), ('C0603', 1)]
[('R0603', 1), ('19.6K', 1)]
[('1nF', 1), ('C0603', 1)]
[('C0603', 1), ('1uF', 1)]
[('2.2uF', 1), ('C0603', 1)]
[('2.2uF', 1), ('C0603', 1)]
[('R0603', 1), ('22K', 1)]
[('R0603', 1), ('22K', 1)]
[('22uF', 1), ('C0603', 1)]
[('R0603', 1), ('483', 1)]
[('53047-05', 2)]
[('ATMEGA32L-8MU', 1), ('QFN50P700X700X100-45N', 1)]

I try'd to search on google, i try'd other code but it wont work for me. Does someone have an idea how to fix this?

Answer 1

If you want to count each element from the second and third elements as single elements just split, extract the second and third elements with itertools.islice and call tuple on the islice object passing it to Counter using a generator expression.:

from collections import Counter
from itertools import islice

with open('test.txt') as f:
    print(Counter(tuple(islice(line.split(), 1, 3)) for line in f))

Output from your example:

Counter({('10uF_Tantalum', 'C0603'): 1, ('22uF', 'C0603'): 1, ('1nF', 'C0603'): 1, ('100nF', 'C0603'): 1, ('1uF', 'C0603'): 1})

If you want a nicer output use str.format and iterate:

with open('test.txt') as f:
    cn = Counter(tuple(islice(line.split(), 1, 3)) for line in f)
    for k, v in cn.items():
        print("{} {} {v}".format(*k, v=v))

Output:

10uF_Tantalum C0603 1
22uF C0603 1
1nF C0603 1
100nF C0603 1
1uF C0603 

Answer 2

Provided that we have data already organized in this way:

elements = [
    ("a", "b"),
    ("c", "d"),
    ("a", "b"),
    ("c", "d"),
    ("a", "b"),
]

We can create a set of unique elements:

elset = set(elements)

And then display how many times each unique element is present in the original list:

for e in elset:
    print e[0], e[1], elements.count(e)