[英]javascript checkbox check all
I'm working on a check all button, but I'm a bit too unfamiliar with javascript to do this part. 我正在使用全选按钮,但是我对JavaScript不太熟悉,无法完成此部分。
Essentially, I have a checkbox at the top of the page, and when you check it, it goes through and changes a checkbox in each row of a table to be checked. 本质上,我在页面顶部有一个复选框,当您选中它时,它将遍历并更改要检查的表的每一行中的复选框。
I've looked around at the similar questions and I know I have to use 我环顾了类似的问题,我知道我必须使用
~~~~.prop('checked', ...)
This is the checkbox which I would like to have check all the boxes in the table. 这是我要选中表中所有复选框的复选框。
<div class="disc-opt" style="float:left">
Adjust All
<div class="make-switch">
<input type="checkbox" class="create-adjustments" />
</div>
</div>
This is the table row layout. 这是表格行的布局。
<tr class="<?= $data['adjusted'] ? "success" : "" ?>">
<td>
Stuff
</td>
<td><?= $data['products_name'] ?></td>
<td><?= $data['total_final_quantity'] ?></td>
<td><?= $data['total_onhand'] ?></td>
<td><?= $data['difference'] ?> </td>
<td><?= $data['difference_cost'] ?></td>
<!-- The Checkbox to be changed -->
<td class = "Adjustbox">
<?php if(!$data['adjusted']): ?>
<div class="make-switch">
<input type="checkbox" name="adjust_products[]"
value="<?= $products_id ?>">
</div>
<?php else: ?>
Adjustment Complete
<?php endif; ?>
</td>
</tr>
Edit: Here's what I'm currently working with(I'm not sure if this is really poorly set up, it's from a bunch of old code I've never touched before today). 编辑:这是我目前正在使用的内容(我不确定这是否设置得很差,它来自一堆我以前从未接触过的旧代码)。 I've made some edits in the code above as well. 我也在上面的代码中做了一些编辑。
function createAdjustments()
{
if($("#create-adjustments").is(':checked'))
{
//turn all on
} else {
//turn all off
}
}
$('#create-adjustments').change(function(e)
{
createAdjustments();
});
$('#create-adjustments').trigger('change');
I've been able to access the element in the table row via the document.ready function, but I couldn't get anything to work when I checked the checkbox. 我已经能够通过document.ready函数访问表格行中的元素,但是当我选中该复选框时,我什么都无法工作。
Here's a picture of what I'm trying to do: 这是我要做什么的图片:
I'm trying to make it so that when I check the checkbox on the top left, it goes through the table and checks all of the checkboxes in the right column. 我试图这样做,以便当我选中左上方的复选框时,它会遍历表格并选中右列中的所有复选框。
Take a look at this I did a similar thing earlier and this did the trick for me. 看看这个,我之前做过类似的事情,这为我带来了窍门。 Pretty much, you create a div with all your input boxes and say to mark all of them as checked if the main one is clicked. 几乎,您创建了一个包含所有输入框的div,并说如果单击主输入框,则将所有输入框标记为已选中。
HTML: HTML:
<label><input type="checkbox" name="sample" class="selectall"/> Select all</label>
<div id="checkboxlist">
<label><input type="checkbox" name="sample[]"/>checkbox1</label><br />
<label><input type="checkbox" name="sample[]"/>checkbox2</label><br />
<label><input type="checkbox" name="sample[]"/>checkbox3</label><br />
<label><input type="checkbox" name="sample[]"/>checkbox4</label><br />
</div>
JAVASCRIPT: JAVASCRIPT:
$('.selectall').click(function() {
if ($(this).is(':checked')) {
$('div input').attr('checked', true);
} else {
$('div input').attr('checked', false);
}
});
If you're talking about ~~~~.prop('checked', ...)
, then you're talking about jQuery. 如果您正在谈论~~~~.prop('checked', ...)
,那么您正在谈论的是jQuery。
In that case if you want to check a checkbox you would want to provide an ID
or class
. 在这种情况下,如果要选中一个复选框,则需要提供一个ID
或class
。 If you don't want , well : 如果您不想要,那么:
$(".make-switch input:checkbox:first").prop('checked',true)
I ended up solving it using this. 我最终用这个解决了。
if($("#create-adjustments").is(':checked'))
{
$("tr").find("td.box").find("div").find("div").prop('class', "switch-on switch-animate");
} else {
$("tr").find("td.box").find("div").find("div").prop('class', "switch-off switch-animate");
}
<label><input type="checkbox" name="sample" class="selectall"/> Select all</label>
<div id="checkboxlist">
<label><input type="checkbox" name="sample[]"/>checkbox1</label><br />
<label><input type="checkbox" name="sample[]"/>checkbox2</label><br />
<label><input type="checkbox" name="sample[]"/>checkbox3</label><br />
<label><input type="checkbox" name="sample[]"/>checkbox4</label><br />
</div>
$('.selectall').click(function() {
if ($(this).is(':checked')) {
$('#checkboxlist input[type="checkbox"').prop('checked', true);
} else {
$('#checkboxlist input[type="checkbox"').prop('checked', false);
}
});
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