正则表达式不匹配6个重复的数字

Question

I am trying to get a regular expression to work but am stumped. What I want is to do the inverse of this:

/(\w)\1{5,}/

This regex does the exact opposite of what I'm trying to do. I would like to get everything but a string that has 6 repeating numbers ie 111111 or 999999 .

Is there a way to use a negative look-around or something with this regex?

Answer 1

You can use this rgex:

/^(?!.*?(\w)\1{5}).*$/gm

RegEx Demo

(?!.*?(\\w)\\1{5}) is a negative lookaahead that will fail the match if there are 6 consecutive same word characters in it.

Answer 2

I'd rather go with the \\d shorthand class for digits since \\w also allows letters and an underscore.

^(?!.*(\d)\1{5}).*$

Regex explanation:

• ^ - Start of string/line anchor
• (?!.*(\\d)\\1{5}) - The negative lookahead checking if after an optional number of characters ( .* ) we have a digit ( (\\d) ) that is immediately followed with 5 identical digits ( \\1{5} ).
• .* - Match 0 or more characters up to the
• $ - End of string/line.

See demo . This regex will allow