Python从逗号分隔值中动态选择值

Question

Suppose I have the following strings:

University of example1
Assistent professor, hello, University of example2
Hello, University of example3

How can I retrieve only the values that contain "University" so that the output will be as follows?

University of example1
University of example2
University of example3

Answer 1

Take each String, split it by comma, and then check each slice for "University".

data = """University of example1
Assistent professor, hello, University of example2
Hello, University of example3"""

data = data.replace("\n",",")   #All one line, split with commas
slices = data.split(",")        #Get each slice
for slice in slices:            #Go through each slice
    if "University" in slice:   #check for magic word
        print slice.strip()     #print out what matches, remove trailing and leading white space

Answer 2

You can turn your string into an array with split and splitlines then use filter or a list comprehension to filter out the ones you don't need.

Something like the below should work:

# This will probably come from your file IRL
# We want a list of strings that we can split later and parse
plaintext = """University of example1
Assistent professor, hello, University of example2
Hello, University of example3"""
lines = plaintext.splitlines()


# Define a function to pass into filter
# You'll want to change this to taste, maybe use a regexp depending on requirements
def is_uni(text):

    # Strip out any leading spaces
    return text.lstrip().startswith("Uni")

for line in lines:
    for uni in filter(is_uni,line.split(',')):
        print uni

Answer 3

data_string = "University of example1
Assistent professor, hello, University of example2
Hello, University of example3"
valid_strings = []
strings = data_string.split(",")
for string in strings:
    if "University" in string:
        valid_strings.append(string)

Use valid_strings as you will.