正则表达式匹配2个字符之间的文本

Question

I have this kind of line :

#RT_POOL_CELL1_1 : RT_CELL_T :=  (NEXT     => 0,

#RT_IS_OK                   : BOOLEAN := TRUE;
#RT_RESULT_UPDATE_TM_INFO.TC_INFO : PUS.TYPES.RESULT_UPDATE_TM_INFO_T := PUS.TYPES.UPDATE_OK;

And I need to take RT_POOL_CELL1_1, RT_IS_OK and RT_RESULT_UPDATE_TM_INFO (without the dot .TC_INFO) in java with regex.

I tried to make that with this regex : \\s*[#][[:ascii:]]\\s*[:|.]

But it doen't work. The thing to know is the word I need to take is always between # and :, they can contains space between word et sign. And if there is a ., I juste take the word before the dot.

Thank's for your help.

Answer 1

You can use this regex based on lookarounds:

(?<=#)[^:.]+?(?= *[:.])

Breakup of regex:

(?<=#)     # makes sure there is preceding #
[^:.]+?    # match anything but : or . (non-greedy)
(?= *[:.]) # makes sure this is followed by 0 or more spaces and : or .

RegEx Demo

Answer 2

To match the word:

(?<=#)[^: .]+(?=.*:)

See live demo .