回声内部函数（PHP）

Question

I have created a function which returns information about a website, based on an array function. The function works like this:

site_info('sitename');

Which returns:

Example Site Name

Using a code similar to this:

 function site_info($info) {
     $array = array('sitename' => 'Example Site Name');
     echo $array[$info];
 }

I wish to print these unformatted and then format them after, for example:

echo '<title>'.site_info('sitename').'</title>';

However, this prints into:

Example Site Name <title></title>

Does anyone have any idea why this is happening? One idea I had was that perhaps because the function is echoing the output, which is then inside of another input it wasn't liking it- if this is the case, is there a work around?

Answer 1

Use return inside function instead of eacho and make sure you are using correct array key like:

 function site_info($info) {
     $array = array('sitename' => 'Example Site Name');
     return $array['sitename']; // in your case there will be $info as key
 }

Answer 2

You have to return the value from the function -

 function site_info($info) {
     $array = array('sitename' => 'Example Site Name'); // ' was missing
     return $array[$info];
 }

And then call the function in echo -

echo '<title>' . site_info('sitename') . '</title>'; // ' was missing