apache cxf-将WSDL转换为Java

Question

I need convert WSDL to Java. I run command line with command wsdl2java SERVICE.WSDL but it resulted in error:

"the system cannot find the path specified"

anyone help me?

Answer 1

According to batch:

@echo off
rem
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rem    distributed with this work for additional information
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rem    to you under the Apache License, Version 2.0 (the
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rem
rem    http://www.apache.org/licenses/LICENSE-2.0
rem
rem    Unless required by applicable law or agreed to in writing,
rem    software distributed under the License is distributed on an
rem    "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
rem    KIND, either express or implied. See the License for the
rem    specific language governing permissions and limitations
rem    under the License.
rem
rem

rem 
rem  invoke the Apache CXF wsdl2java tool
rem 
@setlocal

if not defined CXF_HOME goto set_cxf_home

:cont
if not defined JAVA_HOME goto no_java_home

set TOOLS_JAR=%JAVA_HOME%\lib\tools.jar;

if not exist "%CXF_HOME%\lib\cxf-manifest.jar" goto no_cxf_jar

set CXF_JAR=%CXF_HOME%\lib\cxf-manifest.jar


"%JAVA_HOME%\bin\java" -Xmx128M -Djava.endorsed.dirs="%CXF_HOME%\lib\endorsed" -cp "%CXF_JAR%;%TOOLS_JAR%;%CLASSPATH%" -Djava.util.logging.config.file="%CXF_HOME%\etc\logging.properties" org.apache.cxf.tools.wsdlto.WSDLToJava %*

@endlocal

goto end

:no_cxf_jar
echo ERROR: Unable to find cxf-manifest.jar in %cxf_home/lib
goto end

:no_java_home
echo ERROR: Set JAVA_HOME to the path where the JDK (6.0 or higher) is installed
goto end 

:set_cxf_home
set CXF_HOME=%~dp0..
goto cont

:end

According to me, there can be just one problem, which can generate error you reported. Path %JAVA_HOME%\\lib\\tools.jar doesn't exist. So, please check if enviroment variable JAVA_HOME exists and if it is correctly set.