使用Ajax从URL显示JSON数据

Question

We want to display all the names from our json file into a div using javascript. We tried a lot of things, but we didn't manage to succeed.

json data : http://www.smartbustracking.be/json/data.json

This is what we tried :

<button>get data</button>
<div id="resultJson"></div>


<script type="text/javascript" language="javascript">
             $("button").click(function(){
                    $.getJSON("http://www.smartbustracking.be/json/data.json", function(result){
                        for(var x = 0; x < result.length; x++){

                                $.each(result, function(i, field) {
                                    $("#resultJson").append(field[x].name);
                                }

                        }
                    });
            });

If anyone can help us with this ploblem, that would be great

Thanks in advance !

Answer 1

don't use extra loop inside for loop to extract name.

Your data is like

[0] = {name:"name1"}
[1] = { name: "name2"}

If there is a array inside [0] and you want to extract value from that then you need another loop inside for loop to extract that value like you wanna to pull value of bushaltes .

Try like this

 $("button").click(function() { $.getJSON("http://www.smartbustracking.be/json/data.json", function(result) { console.log(result); for (var x = 0; x < result.length; x++) { $("#resultJson").append(result[x].name); } }); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <button>get data</button> <div id="resultJson"></div> 

Answer 2

you need either the for loop or $.each but not both.

Here's the updated code.

 $("button").click(function(){
        $.getJSON("http://www.smartbustracking.be/json/data.json", function(result){
            $.each(result, function(i, field) {
                $("#resultJson").append(field.name);
            });
        });
   });

and here's the demo

Answer 3

I don't see why you are using jQuery each inside your for loop.

Additionnaly, I think you should use result[x].name instead of field[x].name as you are giving result as parameter of callback function:

$.getJSON("http://www.smartbustracking.be/json/data.json", function(result){
                        for(var x = 0; x < result.length; x++){
                                    $("#resultJson").append(result[x].name);
                        }
                    });

I hope it helps